Question

Для приготовления 500 мл 10%-ного раствора ( d=1.1 г/моль) необходимо ____________граммов карбоната натрия.

Answer 1

Масса 500 мл раствора = 1,1*500=550 гр 
В 550 гр раствора содержится 10% карбоната натрия.
масса карбоната/550=10%/100%
масса карбоната натрия = 550*0,1=5,5 гр 

Answer 2

Calculating the Amount of Sodium Carbonate Needed

To calculate the amount of sodium carbonate needed to prepare a 500 ml 10% solution with a density of 1.1 g/mol, we can use the formula:

Amount of solute (g) = Volume of solution (L) × Concentration of solution (g/L)

Given: - Volume of solution (V) = 500 ml = 0.5 L - Concentration of solution (C) = 10% = 0.1 g/ml - Density of sodium carbonate (d) = 1.1 g/mol

Using the formula, we can calculate the amount of sodium carbonate needed:

Amount of solute (g) = 0.5 L × 0.1 g/ml = 0.05 g

Therefore, to prepare a 500 ml 10% solution with a density of 1.1 g/mol, you would need 0.05 grams of sodium carbonate.