Question

вычислите массу спирта полученного при гидратации 150 г этилена,если практический выход спирта составляет 70%

Answer 1

см. вложение (извини, что неаккуратно)

Answer 2

Calculating the Mass of Alcohol Obtained from the Hydration of 150g of Ethylene

To calculate the mass of alcohol obtained from the hydration of 150g of ethylene, we can use the information provided about the practical yield of alcohol, which is 70%.

Step 1: Calculate the Theoretical Yield of Alcohol The theoretical yield of alcohol can be calculated using the molar mass of ethylene and the stoichiometry of the reaction.

Step 2: Calculate the Mass of Alcohol Obtained The mass of alcohol obtained can be calculated by multiplying the theoretical yield by the practical yield (expressed as a decimal).

Let's proceed with the calculations.

Step 1: Calculate the Theoretical Yield of Alcohol

The molar mass of ethylene (C2H4) is approximately 28.05 g/mol.

The balanced chemical equation for the hydration of ethylene to form alcohol is: C2H4 + H2O → C2H5OH

From the equation, we can see that 1 mole of ethylene produces 1 mole of alcohol.

Step 2: Calculate the Mass of Alcohol Obtained

The mass of alcohol obtained can be calculated using the following formula: Mass of alcohol = Theoretical yield of alcohol * Practical yield

Let's perform the calculations.

The molar mass of ethylene is approximately 28.05 g/mol.

The theoretical yield of alcohol from 150g of ethylene can be calculated as follows: Theoretical yield = (Molar mass of ethylene / Molar mass of alcohol) * Mass of ethylene Theoretical yield = (28.05 g/mol / 46.07 g/mol) * 150g Theoretical yield ≈ 91.17g

Now, we can calculate the mass of alcohol obtained: Mass of alcohol = 91.17g * 0.70 Mass of alcohol ≈ 63.82g

Therefore, the mass of alcohol obtained from the hydration of 150g of ethylene, with a practical yield of 70%, is approximately 63.82g.