Question

Задачу решите Какой объём кислорода можно получить из 61,2 г перекиси водорода?

Answer 1

2H2O2 = 2H2O + O2
n(H2O2) = m/M = 61,2/34 = 1,8 моль
Из уравнения реакции: n(H2O2)/n(O2) = 2/1, n(O2) = n(H2O2)/2 = 1,8/2 = 0,9 моль
V(O2) = n*Vm = 0,9*22,4 = 20,16 л

Answer 2

     61,2 г                 Х л
   2H2O2       ->       O2       +       2H2O
n=2 моль                n = 1 моль
М = 34 г/моль        Vm=22,4 л/моль
m=68 г                    V = 22,4 л

61,2 г Н2О2    -   Х л О2
68 г Н2О2      -   22,4 л О2
V(O2) = 61,2 * 22,4 / 68 =20,16 л

Answer 3

Calculating the Volume of Oxygen from Hydrogen Peroxide

To calculate the volume of oxygen that can be obtained from 61.2 g of hydrogen peroxide, we can use the following steps:

1. Determine the Molar Mass of Hydrogen Peroxide (H2O2): - The molar mass of hydrogen peroxide (H2O2) can be calculated by adding the atomic masses of its constituent elements, which are 2 hydrogen atoms (H) and 2 oxygen atoms (O). - The atomic mass of hydrogen is approximately 1.008 g/mol, and the atomic mass of oxygen is approximately 16.00 g/mol.

2. Calculate the Number of Moles of Hydrogen Peroxide: - Using the given mass of 61.2 g, we can calculate the number of moles of hydrogen peroxide.

3. Use Stoichiometry to Relate Moles of Hydrogen Peroxide to Moles of Oxygen: - The balanced chemical equation for the decomposition of hydrogen peroxide into water and oxygen is: 2 H2O2 (l) → 2 H2O (l) + O2 (g). - From the balanced equation, we can determine the mole ratio of hydrogen peroxide to oxygen.

4. Convert Moles of Oxygen to Volume: - Finally, we can use the ideal gas law to convert the moles of oxygen to volume at standard temperature and pressure (STP).

Let's proceed with the calculations.

Molar Mass of Hydrogen Peroxide (H2O2)

The molar mass of hydrogen peroxide (H2O2) can be calculated as follows: - Molar mass of H2O2 = (2 × molar mass of H) + (2 × molar mass of O)

Calculation of Moles of Hydrogen Peroxide

Using the molar mass of hydrogen peroxide, we can calculate the number of moles from the given mass of 61.2 g.

Stoichiometry to Relate Moles of Hydrogen Peroxide to Moles of Oxygen

From the balanced chemical equation for the decomposition of hydrogen peroxide, we can determine the mole ratio of hydrogen peroxide to oxygen.

Conversion of Moles of Oxygen to Volume

Finally, we can use the ideal gas law to convert the moles of oxygen to volume at standard temperature and pressure (STP).

I will now proceed with the calculations based on the provided information.