Question

В результате взаимодействия аминоуксусной кислоты массой 90г с гидроксидом калия образовалось 100г соли. Вычислите массовую долю соли. (заранее спасибо)

Answer 1

NH2-CH2-COOH+ KOH= NH2-CH2-COOK + H2O

n(NH2C2H3O2)= 90/75= 1,2 моль = n соли

m (NH2C2H2O2K)= 1,2*113= 135,6 г

w= 100/135,6* 100%= 73,7%

Answer 2

NH2CH2COOH+KOH=NH2CH2COOK+H2O

m(NH2CH2COOK)=100г v(NH2CH2COOK)=100/113=0.885моль

 

 v(NH2CH2СOOK)=90/75=1.2 моль           

кислота в избытке v(KOH)=v(NH2CH2COOK)=0.885 моль

m(смеси)=m(KOH)+m(NH2CH2COOH)=0.885*56+90=139.56 г

w(NH2CH2COOK)=100/139.56=0.7165 или 71,65%

 

 

 

 

 

 

Answer 3

Calculation of the Mass Fraction of Salt

To calculate the mass fraction of salt formed from the interaction of 90g of acetic acid with potassium hydroxide, we need to determine the mass of the salt formed.

Given: - Mass of acetic acid (CH3COOH) = 90g - Mass of salt formed = 100g

The mass fraction of the salt can be calculated using the formula:

Mass Fraction = (Mass of Salt / Total Mass) x 100

Substituting the given values into the formula:

Mass Fraction = (100g / (90g + 100g)) x 100

Simplifying the equation:

Mass Fraction = (100g / 190g) x 100

Calculating the mass fraction:

Mass Fraction = 52.63%

Therefore, the mass fraction of the salt formed is approximately 52.63%.