Question

Химики, помогите!!! СПАСИТЕ МОЮ ЖИЗНЬ, МЕНЯ ХИМИЧКА СЪЕСТ!!!! 1) Дано: W(c)=70.6% W(H)=13.7% DH2=51 CxHy-? 2) Рассчитайте массу этилового спирта, полученного гидратацией этилена массой 56г. 3) Рассчитайте массу глюкозы CH6H2O6 необходимую для получения 138 г этилового спирта путем спиртового брожения

Answer 1

Удачи в химии, решил,что мог.

Answer 2

Problem 1: Дано: W(c)=70.6%, W(H)=13.7%, DH2=51+CxHy-?

To solve this problem, we need to find the empirical formula of the compound given the percentages of carbon (C) and hydrogen (H) and the molar mass of hydrogen gas (H2).

The molar mass of hydrogen gas (H2) is 2 g/mol.

Let's assume the molar mass of the compound is 100 g/mol.

To find the empirical formula, we need to determine the number of moles of carbon and hydrogen in 100 g of the compound.

1. Calculate the mass of carbon (C): - Mass of carbon = W(C) * molar mass of the compound - Mass of carbon = 70.6% * 100 g/mol = 70.6 g

2. Calculate the mass of hydrogen (H): - Mass of hydrogen = W(H) * molar mass of the compound - Mass of hydrogen = 13.7% * 100 g/mol = 13.7 g

3. Calculate the number of moles of carbon (C): - Moles of carbon = mass of carbon / molar mass of carbon - Moles of carbon = 70.6 g / 12 g/mol = 5.88 mol

4. Calculate the number of moles of hydrogen (H): - Moles of hydrogen = mass of hydrogen / molar mass of hydrogen - Moles of hydrogen = 13.7 g / 1 g/mol = 13.7 mol

5. Find the empirical formula by dividing the number of moles of each element by the smallest number of moles: - Divide the moles of carbon and hydrogen by 5.88 (the smallest number of moles): - Moles of carbon = 5.88 mol / 5.88 mol = 1 mol - Moles of hydrogen = 13.7 mol / 5.88 mol ≈ 2.33 mol

- Round the moles of hydrogen to the nearest whole number: - Moles of hydrogen ≈ 2 mol

- The empirical formula is CH2.

Therefore, the empirical formula of the compound is CH2.

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