Question

B2S3 + HNO3 Прошу написать со всеми коэффициентами.

Answer 1

B2S3+24HNO3 - > 2H3BO3 + 3H2SO4+6H20 +24NO2

Answer 2

B2S3+24HNO3=2H3BO3+3 H2SO4+6H2O+24NO2 
скорее всего так)

Answer 3

Chemical Equation for the Reaction of B2S3 with HNO3

The balanced chemical equation for the reaction of B2S3 with HNO3 is as follows:

B2S3 + 6HNO3 → 3H2SO4 + 2NO + 3H2O

This balanced equation represents the reaction between boron(III) sulfide (B2S3) and nitric acid (HNO3), resulting in the formation of sulfuric acid (H2SO4), nitrogen monoxide (NO), and water (H2O) [[1]].

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