Question

1. Закончите уравнения и расставьте коэффициенты методом электронного баланса. Fe + HF= 2. Закончите уравнения реакций: Fe + O2 = Fe + CuCO3 = Fe(OH)2 = Fe + HMnO4 = Fe(OH)2 + H3PO4= Fe(OH)2 + CuCL2= ______________ Сделайте плез

Answer 1

2Fe+6HF=2FeF3+3H2
Fe(0)-3e=Fe(+3) | *2 - восстановитель, окисление
2H(+1)+2e=H2(0) | *3 - окислитель, восстановление
Fe+O2=FeO
Fe+CuCO3=FeCO3+Cu
Fe(OH)2=FeO+H2O
3Fe(OH)2+2H3PO4=Fe3(PO4)2+3H2O
Fe(OH)2+CuCl2=реакции не будет, так как Fe(OH)2 - нерастворимое основание
Fe+2HMnO4=Fe(MnO4)2+H2 (точно не уверена насчет этого)

Answer 2

Balancing Equations using the Electron Balance Method

To balance the equation Fe^3+ + HF = ?, we can use the electron balance method. This method involves balancing the number of electrons gained and lost during the reaction.

The electron balance method involves the following steps:

1. Assign oxidation numbers to each element in the equation. 2. Determine the change in oxidation number for each element. 3. Balance the equation by adding coefficients to the reactants and products to ensure that the total number of electrons gained equals the total number of electrons lost.

Let's apply this method to the given equation:

Fe^3+ + HF = ?

1. Assign oxidation numbers: - The oxidation number of Fe in Fe^3+ is +3. - The oxidation number of H in HF is +1. - The oxidation number of F in HF is -1.

2. Determine the change in oxidation number: - Fe: +3 to 0 (reduction) - H: +1 to +1 (no change) - F: -1 to 0 (oxidation)

3. Balance the equation: - To balance the change in oxidation number for Fe, we need three electrons on the left side of the equation. - The balanced equation is: 3Fe^3+ + 6HF = 3Fe + 6H^+ + 6F^-

Therefore, the balanced equation is 3Fe^3+ + 6HF = 3Fe + 6H^+ + 6F^-.

Balancing Other Equations

Now let's balance the other equations you provided using the same method:

1. Fe^3+ + O2 = ? - Assign oxidation numbers: - Fe: +3 - O: -2 - Determine the change in oxidation number: - Fe: +3 to 0 (reduction) - O: -2 to 0 (oxidation) - Balance the equation: - The balanced equation is: 4Fe^3+ + 3O2 = 2Fe2O3

2. Fe^3+ + CuCO3 = ? - Assign oxidation numbers: - Fe: +3 - Cu: +2 - C: +4 - O: -2 - Determine the change in oxidation number: - Fe: +3 to 0 (reduction) - Cu: +2 to +2 (no change) - C: +4 to +4 (no change) - O: -2 to 0 (oxidation) - Balance the equation: - The balanced equation is: 2Fe^3+ + 3CuCO3 = 2Fe + 3CuO + 3CO2

3. Fe(OH)2 + H3PO4 = ? - Assign oxidation numbers: - Fe: +2 - H: +1 - O: -2 - P: +5 - Determine the change in oxidation number: - Fe: +2 to 0 (reduction) - H: +1 to +1 (no change) - O: -2 to 0 (oxidation) - P: +5 to +5 (no change) - Balance the equation: - The balanced equation is: 3Fe(OH)2 + 2H3PO4 = Fe3(PO4)2 + 6H2O

4. Fe(OH)2 + CuCl2 = ? - Assign oxidation numbers: - Fe: +2 - Cu: +2 - Cl: -1 - O: -2 - Determine the change in oxidation number: - Fe: +2 to 0 (reduction) - Cu: +2 to +2 (no change) - Cl: -1 to 0 (oxidation) - O: -2 to 0 (oxidation) - Balance the equation: - The balanced equation is: 3Fe(OH)2 + 2CuCl2 = Fe3O4 + 6H2O + 2CuCl

I hope this helps! Let me know if you have any further questions.