Question

"выведите формулу вещества содержащего К-26.53% Cr-35.57% O-38,10%"

Answer 1

Вот так вроде. проверяй

Answer 2

Chemical Formula Calculation for Substance with K-26.53%, Cr-35.57%, O-38.10%

To calculate the chemical formula for a substance containing potassium (K) 26.53%, chromium (Cr) 35.57%, and oxygen (O) 38.10%, we can use the concept of molar ratios and percentages to determine the subscripts for each element in the chemical formula.

First, we need to convert the percentages of each element into moles. Then, we can find the smallest whole number ratio of the moles of each element to determine the chemical formula.

Step 1: Convert Percentages to Moles

We can start by assuming we have 100 grams of the substance. This allows us to directly convert the percentages to grams.

- Potassium (K): 26.53 grams - Chromium (Cr): 35.57 grams - Oxygen (O): 38.10 grams

Next, we convert the grams to moles using the molar mass of each element.

- Potassium (K): - Molar mass of K = 39.10 g/mol - Moles of K = 26.53 g / 39.10 g/mol = 0.678 moles

- Chromium (Cr): - Molar mass of Cr = 51.996 g/mol - Moles of Cr = 35.57 g / 51.996 g/mol = 0.685 moles

- Oxygen (O): - Molar mass of O = 16.00 g/mol - Moles of O = 38.10 g / 16.00 g/mol = 2.381 moles

Step 2: Determine the Simplest Whole Number Ratio

To find the simplest whole number ratio of the moles of each element, we divide each mole value by the smallest mole value obtained.

- Potassium (K): 0.678 moles / 0.678 = 1 - Chromium (Cr): 0.685 moles / 0.678 ≈ 1.011 - Oxygen (O): 2.381 moles / 0.678 ≈ 3.515

Rounding these values to the nearest whole number, we get approximately:

- Potassium (K): 1 - Chromium (Cr): 1 - Oxygen (O): 4

Chemical Formula

Based on the mole ratios, the chemical formula for the substance containing potassium (K) 26.53%, chromium (Cr) 35.57%, and oxygen (O) 38.10% is KCrO4.