Question

2. Написать молекулярное, полное и сокращенное ионное уравнение реакции между растворами (1 уравнение на выбор)а) гидроксидом натрия и серной кислотой; быстрее горю

Answer 1

2NaOH+H2SO4=Na2SO4+2H2O
2Na(+)+2OH(-)+2H(+)+SO4(2-)=2Na(+)+SO4(2-)+2H2O
H(+)+OH(-)=H2O

Answer 2

Molecular, Complete, and Ionic Equations for the Reaction Between Sodium Hydroxide and Sulfuric Acid

Molecular Equation: The molecular equation for the reaction between sodium hydroxide (NaOH) and sulfuric acid (H2SO4) is as follows: ``` 2NaOH + H2SO4 → Na2SO4 + 2H2O ``` [[2 #]]

Complete Ionic Equation: The complete ionic equation breaks down each compound into its individual ions: ``` 2Na⁺ + 2OH⁻ + H⁺ + SO4²⁻ → 2Na⁺ + SO4²⁻ + 2H2O ``` [[2 #]]

Net Ionic Equation: The net ionic equation focuses on the ions that actually participate in the reaction: ``` 2OH⁻ + H⁺ → 2H2O ``` [[2 #]]

This reaction is a neutralization reaction, where an acid and a base react to form a salt and water. In this case, sodium sulfate (Na2SO4) is formed as the salt, and water is produced as a byproduct.

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