Question

1. Напишите уравнения всех возможных реакций между веществами: СuO, H2SO4(к), NaOH, SO2 , NH3 2.Напишите уравнения реакций для превращений: N2→NH3→NH4 Сl→ NH3→ NO уравнение 3 запишите в ТЭД 3. Задача. Какой объем хлороводорода получится при реакции 20л хлора с водородом, если выход составляет 80 %?

Answer 1

Решение см. во вложении

Answer 2

Chemical Reactions Equations

1. The equations for the reactions between the given substances are as follows: - CuO + H2SO4(к) → CuSO4 + H2O - NaOH + SO2 → Na2SO3 + H2O - NH3 + HCl → NH4Cl

These equations are based on chemical reactions involving copper oxide (CuO), sulfuric acid (H2SO4), sodium hydroxide (NaOH), sulfur dioxide (SO2), and ammonia (NH3).

2. The transformations for the given reactions are: - N2 → NH3 → NH4Cl - NH3 → NO

These transformations represent the conversion of nitrogen (N2) to ammonia (NH3) and then to ammonium chloride (NH4Cl), as well as the conversion of ammonia (NH3) to nitric oxide (NO).

Task: Volume of Hydrochloric Acid Produced

To calculate the volume of hydrochloric acid produced when 20 liters of chlorine reacts with hydrogen, given an 80% yield, we can use the following equation:

Cl2 + H2 → 2HCl

Given that the yield is 80%, the actual amount of hydrochloric acid produced can be calculated using the stoichiometry of the reaction. Since the reaction produces 2 moles of HCl for every 1 mole of Cl2, the amount of HCl produced can be calculated as follows:

80% of 20 liters of Cl2 = 0.8 * 20 = 16 liters of HCl

Therefore, the volume of hydrochloric acid produced is 16 liters.

I hope this helps! If you have further questions, feel free to ask.