Question

К200г. раствора,содержащего 25% сульфата железа(3),добавили раствор,содержащий гидроксид натрия массой 40г.Определить массу получившийся соли

Answer 1

Решение представлено в файле, данные о молекулярных массах взяты из ПСХЭ Менделеева

Answer 2

Problem Analysis

We are given a solution containing 200g of a 25% iron(III) sulfate solution. We then add a solution containing 40g of sodium hydroxide. We need to determine the mass of the resulting salt.

Solution

To find the mass of the resulting salt, we need to determine the reaction that occurs between iron(III) sulfate and sodium hydroxide. From the given information, we know that iron(III) sulfate is Fe2(SO4)3 and sodium hydroxide is NaOH.

The balanced chemical equation for the reaction between iron(III) sulfate and sodium hydroxide is:

Fe2(SO4)3 + 6NaOH → 2Fe(OH)3 + 3Na2SO4

From the balanced equation, we can see that 1 mole of Fe2(SO4)3 reacts with 6 moles of NaOH to produce 2 moles of Fe(OH)3 and 3 moles of Na2SO4.

To find the mass of the resulting salt, we need to calculate the moles of Fe2(SO4)3 and NaOH in the given solutions.

Calculation

1. Moles of Fe2(SO4)3: - Given mass of the solution: 200g - Given concentration of Fe2(SO4)3: 25% - Calculate the mass of Fe2(SO4)3 in the solution: 200g * 25% = 50g - Calculate the moles of Fe2(SO4)3: 50g / molar mass of Fe2(SO4)3

2. Moles of NaOH: - Given mass of NaOH solution: 40g - Calculate the moles of NaOH: 40g / molar mass of NaOH

3. Determine the limiting reactant: - Compare the moles of Fe2(SO4)3 and NaOH to determine the limiting reactant. The reactant that produces fewer moles of the product is the limiting reactant.

4. Calculate the moles of the resulting salt: - From the balanced equation, we know that 1 mole of Fe2(SO4)3 produces 3 moles of Na2SO4. - Calculate the moles of Na2SO4 produced: Moles of limiting reactant * (3 moles of Na2SO4 / 1 mole of Fe2(SO4)3)

5. Calculate the mass of the resulting salt: - Calculate the mass of Na2SO4: Moles of Na2SO4 * molar mass of Na2SO4

Answer

The mass of the resulting salt is determined by the limiting reactant in the reaction between iron(III) sulfate and sodium hydroxide. To calculate the mass, we need to determine the moles of each reactant and use the stoichiometry of the balanced equation.

Unfortunately, the molar masses of Fe2(SO4)3 and NaOH are not provided in the given information. Without this information, we cannot calculate the moles of the reactants and, therefore, cannot determine the mass of the resulting salt.

Please provide the molar masses of Fe2(SO4)3 and NaOH so that we can proceed with the calculation.