Вопрос задан 28.04.2019 в 10:09. Предмет Химия. Спрашивает Гагарин Васик.

Расставьте коэффициенты и рассмотрите реакцию с точки зрения окисления - восстановления: укажите

степени окисления элементов, окислитель, восстановитель, переход электронов: HCI + MnO2 → CI2 + MnCI2 + H2O
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Reaction Analysis: Oxidation-Reduction Reaction

The given chemical equation is:

HCI + MnO2 → CI2 + MnCI2 + H2O

To analyze this reaction from the perspective of oxidation-reduction (redox), we need to determine the oxidation states (or oxidation numbers) of the elements involved. The oxidation state is a measure of the degree of oxidation or reduction of an atom in a compound.

Let's assign oxidation states to the elements in the equation:

- Hydrogen (H) typically has an oxidation state of +1 in compounds, except when it is bonded to a metal or boron, where it has an oxidation state of -1. - Chlorine (Cl) typically has an oxidation state of -1 in compounds, except when it is bonded to oxygen or a more electronegative element, where it can have positive oxidation states. - Oxygen (O) typically has an oxidation state of -2 in compounds, except when it is in peroxides (such as H2O2) where it has an oxidation state of -1, or when it is bonded to fluorine (F) where it has a positive oxidation state. - Manganese (Mn) can have various oxidation states, but in this reaction, it is in the +4 oxidation state.

Now, let's determine the changes in oxidation states for the elements involved in the reaction:

- Hydrogen (H) in HCl is already in its lowest possible oxidation state (+1), and it remains unchanged in the reaction. - Chlorine (Cl) in HCl is in the -1 oxidation state and is oxidized to the 0 oxidation state in Cl2. - Oxygen (O) in MnO2 is in the -2 oxidation state and is reduced to the -1 oxidation state in H2O. - Manganese (Mn) in MnO2 is in the +4 oxidation state and is reduced to the +2 oxidation state in MnCl2.

Based on the changes in oxidation states, we can identify the oxidizing agent and the reducing agent in the reaction:

- The oxidizing agent is the species that gets reduced (gains electrons). In this case, MnO2 is the oxidizing agent since manganese (Mn) is reduced from the +4 to the +2 oxidation state. - The reducing agent is the species that gets oxidized (loses electrons). In this case, HCl is the reducing agent since chlorine (Cl) is oxidized from the -1 to the 0 oxidation state.

The transfer of electrons occurs from the reducing agent (HCl) to the oxidizing agent (MnO2). In this reaction, electrons are transferred from HCl to MnO2.

To summarize the reaction from the perspective of oxidation-reduction:

- The reducing agent: HCl - The oxidizing agent: MnO2 - The transfer of electrons: From HCl to MnO2

Please note that the reaction is not balanced. Balancing the equation is necessary to ensure that the number of atoms of each element is the same on both sides of the equation.

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