Question

при электролизе расплава хлорида кальция на аноде выделилось 11,2 ( н.у.)хлора.Определите массу образующегося кальция катоде(пр.20).

Answer 1

CaCl2 ====== Ca + Cl2

Ca(+2) + 2e = Ca(0)

2Cl(-) - 2e = Cl2(0)

n(Cl2) = V/Vm = 11,2л/22,4л/моль = 0,5 моль

По уравнению реакции n(Ca) = n(Cl2) = 0,5моль

m(Ca) = n x M = 0,5 моль х 40г/моль = 20г 

Answer 2

Electrolysis of Calcium Chloride and Calculation of Calcium Mass

When calcium chloride is electrolyzed, chlorine gas is produced at the anode. The amount of chlorine gas produced can be used to determine the mass of calcium formed at the cathode. In this case, 11.2 normal liters of chlorine gas were produced at the anode.

According to source the relationship between the volume of chlorine gas produced and the mass of calcium formed at the cathode is given by the following equation:

2Cl2 + 2e- -> 2Cl-

This equation shows that for every 2 moles of electrons, 2 moles of chlorine gas are produced. Therefore, the number of moles of chlorine gas produced can be calculated using the ideal gas law.

Using the ideal gas law equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature, we can calculate the number of moles of chlorine gas produced.

Given that the volume of chlorine gas produced is 11.2 normal liters and the temperature and pressure are not provided, we can assume standard temperature and pressure (STP) for the calculation, where T = 273 K and P = 1 atm.

Using the molar volume of a gas at STP (22.4 L/mol), we can calculate the number of moles of chlorine gas produced.

Once the number of moles of chlorine gas produced is known, we can use the stoichiometry of the reaction to determine the number of moles of electrons and, consequently, the mass of calcium formed at the cathode.

Let's calculate the mass of calcium formed at the cathode using the information provided.