Question

Закончить и уравнять ионно-электронным методом уравнение реакции: S + HNO3 —>

Answer 1

S + 6 HNO3 = 2 H2O + H2SO4 + 6 NO2

S(0)+6N(+5)=S(+6)+6N(+4)

S(0)-6e=S(+6)            I1 восстановитель, окисление

N(+5)+e=N(+4)     I2 окислитель, восстановление

Answer 2

Balancing the Reaction Equation: S + HNO3 -> ?

To balance the chemical equation: S + HNO3 -> ?, we need to ensure that the number of atoms of each element is the same on both sides of the equation. We can balance the equation using the ion-electron method.

The ion-electron method involves the following steps:

Step 1: Write the unbalanced equation. S + HNO3 -> ?

Step 2: Separate the equation into half-reactions. Half-reaction 1: S -> ? Half-reaction 2: HNO3 -> ?

Step 3: Balance the atoms other than hydrogen and oxygen. In this case, we only need to balance the sulfur (S) atom.

Step 4: Balance the oxygen atoms by adding water (H2O) molecules. In the half-reaction with HNO3, there are 3 oxygen atoms on the right side. To balance this, we add 3 water molecules (H2O) to the left side.

Step 5: Balance the hydrogen atoms by adding hydrogen ions (H+). In the half-reaction with HNO3, there is 1 hydrogen atom on the left side. To balance this, we add 2 hydrogen ions (H+) to the right side.

Step 6: Balance the charges by adding electrons (e-). In the half-reaction with HNO3, the charge on the left side is 0, while the charge on the right side is +1. To balance this, we add 1 electron (e-) to the left side.

Step 7: Multiply the half-reactions by appropriate coefficients to equalize the number of electrons transferred. In this case, we need to multiply the first half-reaction by 6 and the second half-reaction by 2 to equalize the number of electrons transferred.

Step 8: Add the balanced half-reactions together and cancel out common terms. After adding the balanced half-reactions together, we can cancel out the common terms to obtain the balanced equation.

The balanced equation for the reaction S + HNO3 -> ? is:

6S + 8HNO3 -> 6H2SO4 + 8NO + 2H2O

Please note that this is a balanced equation obtained using the ion-electron method. The reaction may have different products depending on the reaction conditions.