Question

Сколько граммов цинка необхолимо для получения 56 г оксида цинка

Answer 1

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Answer 2

Calculating the Amount of Zinc Required to Obtain 56g of Zinc Oxide

To calculate the amount of zinc required to obtain 56g of zinc oxide, we can use stoichiometry to determine the molar ratio between zinc and zinc oxide. From the balanced chemical equation for the formation of zinc oxide, we know that 1 mole of zinc reacts with 1 mole of oxygen to produce 1 mole of zinc oxide.

Given that the molar mass of zinc is approximately 65.38 g/mol and the molar mass of oxygen is approximately 16.00 g/mol, we can calculate the molar mass of zinc oxide, which is the sum of the molar masses of zinc and oxygen.

The molar mass of zinc oxide (ZnO) = molar mass of zinc (Zn) + molar mass of oxygen (O) = 65.38 g/mol + 16.00 g/mol = 81.38 g/mol.

Using this information, we can calculate the amount of zinc required to obtain 56g of zinc oxide.

Calculation: - Molar mass of zinc oxide (ZnO) = 81.38 g/mol - Given mass of zinc oxide (ZnO) = 56g

The number of moles of zinc oxide (ZnO) = Given mass / Molar mass = 56g / 81.38 g/mol

Now, we can use the stoichiometric ratio to find the amount of zinc required.

Stoichiometric Ratio: - 1 mole of zinc reacts with 1 mole of oxygen to produce 1 mole of zinc oxide.

Therefore, the amount of zinc required = Number of moles of zinc oxide (ZnO) * Molar mass of zinc (Zn)

Let's calculate the amount of zinc required using the given information.

Answer: The amount of zinc required to obtain 56g of zinc oxide is approximately calculated to be:

 / 81.38 g/mol * 65.38 g/mol = 45g

So, approximately 45 grams of zinc is required to obtain 56g of zinc oxide.