Question

В 100 мл водного раствора содержится 11,71г сахарозы С12Н22О11 . Чему равно осмотического давления раствора при 25 0С? Помогите решить, нужно все подробно

Answer 1

Π=С*R*T
число молей сахарозы в исходном растворе
n=C*V=0,5*0,1=0,05 моль
концентрация раствора после разбавления стала
С=n/V=0,05/0,4=0,125моль/л=0,125*10^3 моль/м^3
R=8.31
T=273+25=298K

π=0,125*10^3 *8,31*298=309547,5Па=309,5 кПа

Answer 2

Calculating Osmotic Pressure of a Solution

To calculate the osmotic pressure of a solution, we can use the formula:

π = iMRT

Where: - π = osmotic pressure - i = van't Hoff factor (the number of particles the solute will produce in solution) - M = molarity of the solution (moles of solute per liter of solution) - R = ideal gas constant (0.0821 L·atm/(K·mol)) - T = temperature in Kelvin

Given Information

We are given that in 100 ml of the solution, there is 11.71g of sucrose (C12H22O11). We need to calculate the osmotic pressure of the solution at 25°C.

Calculating Molarity (M)

First, we need to calculate the molarity of the solution. The molarity (M) is calculated using the formula:

M = (moles of solute) / (volume of solution in liters)

To find the moles of sucrose, we can use its molar mass, which is 342.3 g/mol.

Moles of sucrose = (mass of sucrose) / (molar mass of sucrose)

Moles of sucrose = 11.71g / 342.3 g/mol

Let's calculate the moles of sucrose.

11.71g / 342.3 g/mol = 0.03424 moles of sucrose

Now, we can calculate the molarity of the solution.

M = (0.03424 moles) / (0.1 L)

M = 0.3424 M

Calculating Osmotic Pressure (π)

Now that we have the molarity, we can calculate the osmotic pressure using the formula:

π = iMRT

The van't Hoff factor (i) for sucrose is 1, as sucrose does not dissociate into ions in solution.

π = (1)(0.3424 M)(0.0821 L·atm/(K·mol))(25 + 273.15 K)

Let's calculate the osmotic pressure.

π = (1)(0.3424)(0.0821)(298.15)

π ≈ 8.43 atm

Answer

The osmotic pressure of the solution at 25°C is approximately 8.43 atm.