Question

Вычислите, сколько граммов гидроксида натрия необходимо для полной нейтрализации раствора, содержащего 9,8 граммов серной кислоты

Answer 1

2NaOH+H2SO4=Na2SO4+2H2O M(NaOH)2моль=80 М(Н2SO4)=98 х:80=9.8:98 х=(80*9.8):98=8

Answer 2

Calculating the Amount of Sodium Hydroxide Needed for Neutralization

To calculate the amount of sodium hydroxide (NaOH) needed to neutralize the sulfuric acid (H2SO4) solution, we can use the balanced chemical equation for the neutralization reaction between sodium hydroxide and sulfuric acid:

H2SO4 + 2NaOH → Na2SO4 + 2H2O

According to the balanced chemical equation, 1 mole of sulfuric acid reacts with 2 moles of sodium hydroxide.

Calculation Steps

1. Calculate the number of moles of sulfuric acid present in the solution using the given mass of sulfuric acid. 2. Use the mole ratio from the balanced chemical equation to determine the number of moles of sodium hydroxide required. 3. Convert the moles of sodium hydroxide to grams.

Calculation

1. Number of Moles of Sulfuric Acid: - Given mass of sulfuric acid = 9.8 grams - The molar mass of sulfuric acid (H2SO4) is approximately 98.08 g/mol. - Number of moles of sulfuric acid = Given mass / Molar mass - Number of moles of sulfuric acid = 9.8 g / 98.08 g/mol - Number of moles of sulfuric acid ≈ 0.1 moles

2. Number of Moles of Sodium Hydroxide Required: - According to the balanced chemical equation, 1 mole of sulfuric acid reacts with 2 moles of sodium hydroxide. - Number of moles of sodium hydroxide required = (Number of moles of sulfuric acid) * 2 - Number of moles of sodium hydroxide required ≈ 0.1 moles * 2 - Number of moles of sodium hydroxide required ≈ 0.2 moles

3. Converting Moles to Grams: - The molar mass of sodium hydroxide (NaOH) is approximately 40.00 g/mol. - Mass of sodium hydroxide required = Number of moles * Molar mass - Mass of sodium hydroxide required ≈ 0.2 moles * 40.00 g/mol - Mass of sodium hydroxide required ≈ 8.0 grams

Therefore, approximately 8.0 grams of sodium hydroxide are needed for the complete neutralization of the sulfuric acid solution containing 9.8 grams of sulfuric acid.

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