Question

№1 сколько моль вещества содержится в 22 г.углекислого газа ? №2 сколько моль вещества содержится в 27 г. воды ? №3 какова масса 112 л паров воды?

Answer 1

№1Решение М(СО2)=12+16*2=44г/моль

                   n(СО2)=22г:44г/моль=0,5 моль 

 Ответ n(СО2) 0,5 моль 

№2 Решение М(Н2О)=1*2+16=18г/моль

                    n(Н2О)=27г:18г/моль=1,5 моль 

 Ответ n(Н2О) 1,5 моль

Answer 2

1)n = m/M = 22г/44г/моль=0.5 моль

2) n = m/M = 27г/18г/моль = 1.5 моль

3) n = V/Vm = 112л/22.4 л/моль = 5 моль

n = m/M

m = M*n = 18 г/моль*5 моль = 3.6 г

Answer 3

Answer:

№1: To determine the number of moles of carbon dioxide (CO2) in 22 grams of the substance, we need to use the molar mass of CO2. The molar mass of carbon dioxide is calculated by adding up the atomic masses of carbon (C) and oxygen (O). The atomic mass of carbon is approximately 12.01 grams per mole, and the atomic mass of oxygen is approximately 16.00 grams per mole.

Therefore, the molar mass of CO2 is: 12.01 g/mol (carbon) + 16.00 g/mol (oxygen) + 16.00 g/mol (oxygen) = 44.01 g/mol

To find the number of moles, we divide the given mass by the molar mass: 22 g / 44.01 g/mol ≈ 0.499 moles of CO2

№2: To determine the number of moles of water (H2O) in 27 grams of the substance, we need to use the molar mass of water. The molar mass of water is calculated by adding up the atomic masses of hydrogen (H) and oxygen (O). The atomic mass of hydrogen is approximately 1.01 grams per mole, and the atomic mass of oxygen is approximately 16.00 grams per mole.

Therefore, the molar mass of H2O is: 2 * 1.01 g/mol (hydrogen) + 16.00 g/mol (oxygen) = 18.02 g/mol

To find the number of moles, we divide the given mass by the molar mass: 27 g / 18.02 g/mol ≈ 1.498 moles of H2O

№3: To determine the mass of 112 liters of water vapor, we need to use the density of water vapor and the volume given.

The density of water vapor at standard temperature and pressure (STP) is approximately 0.804 grams per liter.

Therefore, the mass of 112 liters of water vapor is: 0.804 g/L * 112 L = 90.048 grams

So, the mass of 112 liters of water vapor is approximately 90.048 grams.

Please note that the values provided are approximate and may vary slightly depending on the specific conditions and sources used for calculation.

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