Question

При пропускании сероводорода обьемом 2,8л через избыток раствора сульфата меди образуется осадок массой 11,4г. Определите массовую долю выхода продукта реакции

Answer 1

 составим  уравнение H2S+CuSO4=CuS+H2SO4    Н2S газ  1  моль его  занимает  22,4  литра в реакцию  вступает2,8 литра  сероводорода найдем  сколько получится  осадка  сульфида   меди  меди   решаем    2,8*96(это масса  1  моля  сульфида  меди)  и делим  на  22,4=12  гр  это должно столько получится  а  получили  11,4  гр находим   массовую долю   выхода  продукта  11,4:12*100=95%

Answer 2

Calculating the Mass Fraction of the Reaction Product

To calculate the mass fraction of the reaction product, we can use the given information about the volume of hydrogen sulfide passed through an excess of copper sulfate solution and the mass of the resulting precipitate.

Given: - Volume of hydrogen sulfide (H2S) = 2.8 L - Mass of precipitate (CuS) = 11.4 g

We can use the stoichiometry of the reaction to determine the mass fraction of the reaction product.

The balanced chemical equation for the reaction between hydrogen sulfide and copper sulfate is:

H2S + CuSO4 → CuS + H2SO4

From the balanced chemical equation, we can see that 1 mole of hydrogen sulfide reacts with 1 mole of copper sulfate to produce 1 mole of copper sulfide.

Using the molar mass of CuS and the given mass of the precipitate, we can calculate the moles of CuS formed and then determine the mass fraction of the reaction product.

Calculation Steps:

1. Calculate the moles of CuS formed. 2. Determine the mass fraction of the reaction product.

Step 1: Calculate the Moles of CuS Formed

The molar mass of CuS (copper sulfide) is the sum of the atomic masses of copper (Cu) and sulfur (S). - Molar mass of Cu = 63.55 g/mol - Molar mass of S = 32.07 g/mol

Molar mass of CuS = 63.55 g/mol + 32.07 g/mol = 95.62 g/mol

Moles of CuS = Mass of CuS / Molar mass of CuS Moles of CuS = 11.4 g / 95.62 g/mol Moles of CuS ≈ 0.1193 moles

Step 2: Determine the Mass Fraction of the Reaction Product

The mass fraction of the reaction product (CuS) can be calculated using the following formula: Mass fraction = (Mass of CuS formed / Total mass of products) * 100%

The total mass of products is the mass of CuS formed.

Mass fraction = (11.4 g / 11.4 g) * 100% Mass fraction ≈ 100%

The mass fraction of the reaction product (CuS) is approximately 100%.

This indicates that the reaction proceeded to completion, and the entire mass of the product is accounted for in the given mass of the precipitate.