Question

Який об'єм газу утворюєтся, якщо спалити вуглець масою 36г

Answer 1

Смотри, уравнение С+О2=СО2, мольные отношения 1 к 1. Значит кол-во моль О2= кол-ву моль С, и равно кол-ву моль СО2. n(O2)=2моль. думаю умеешь находить. 

А значит, кол-во моль газа= 2 моль. Т.К. не указано , что тут особые условия, будем считать, что 1 моль газа занимает объем 22,4 литра. Тоесть 2 моль займет 44,8л. 

Ответ: Объем выделившегося газа равен 44,8 л

Answer 2

Calculating the Volume of Gas Produced by Burning 36g of Carbon

To calculate the volume of gas produced by burning 36g of carbon, we can use the concept of stoichiometry from chemistry. When carbon is burned, it reacts with oxygen to produce carbon dioxide gas. The balanced chemical equation for this reaction is:

C + O2 → CO2

According to stoichiometry, 1 mole of carbon reacts with 1 mole of oxygen to produce 1 mole of carbon dioxide. The molar mass of carbon is approximately 12 g/mol, and the molar mass of carbon dioxide is approximately 44 g/mol.

Using this information, we can calculate the volume of carbon dioxide gas produced by burning 36g of carbon.

Calculation

1. Calculate the moles of carbon in 36g: - Moles of carbon = Mass of carbon / Molar mass of carbon - Moles of carbon = 36g / 12 g/mol - Moles of carbon = 3 moles

2. Calculate the moles of carbon dioxide produced: - Since the balanced chemical equation shows a 1:1 ratio between carbon and carbon dioxide, the moles of carbon dioxide produced will also be 3 moles.

3. Use the ideal gas law to calculate the volume of gas produced: - The ideal gas law is given by the equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

- Assuming standard temperature and pressure (STP) conditions (0°C and 1 atm), the molar volume of an ideal gas is approximately 22.4 liters/mol.

- Therefore, the volume of carbon dioxide gas produced by burning 36g of carbon at STP can be calculated as: - Volume = Moles of gas * Molar volume - Volume = 3 moles * 22.4 L/mol - Volume ≈ 67.2 liters

Conclusion

Burning 36g of carbon would produce approximately 67.2 liters of carbon dioxide gas at standard temperature and pressure (STP).

This information is based on the stoichiometry of the chemical reaction and the ideal gas law.