Question

Хватит ли 45 л кислород на полное сжигание 24г углерода а) хватит, кислород в избытке в) углерод не горит с) не хватит, углерод в недостатке д) не хватит, кислород в неостатке е) хватит, углерод в избытке Для того, чтобы отличить раствор карбоната натрия от раствора гидроксида натрия нужно использовать а) раствор гидроксида калия в) раствор соляной кислоты с) раствор нитрата калия д) раствор хлорида натрия е) воду Сумма коэффициентов в молекулярном уравнении реакции между гидроксидом бария и серной кислотой а) 4 в)3 с)7 д)6е)5ПЛИИЗ ПОМОГИТЕ ПОЖАЛУЙСТА С РЕШЕНИЕМ !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

Хватит, количество моль кислорода будет больше, чем углерода, еще и в избытке будет - А
раствор соляной кислоты, т. как в реакции с карбонатом натрия выделяется углекислый газ, а в реакции с гидроксидом - нет - В
1Ва(ОН)2+ 1Н2SO4= 1BaSO4 + 2H2O (единицы поставлены для пущего убеждения) - сумма равна пяти - Е

Answer 2

Answer:

To determine whether 45 L of oxygen is sufficient for the complete combustion of 24 g of carbon, we can use the balanced chemical equation for the combustion of carbon:

C(s) + O2(g) → CO2(g)

The balanced chemical equation shows that 1 mole of carbon reacts with 1 mole of oxygen to produce 1 mole of carbon dioxide. From this, we can calculate the amount of oxygen needed to completely combust 24 g of carbon.

The molar mass of carbon is 12 g/mol, and the molar mass of oxygen is 16 g/mol. Using these molar masses, we can calculate the moles of carbon and the moles of oxygen required for the reaction.

1. Calculate Moles of Carbon: - Moles of Carbon = Mass of Carbon / Molar Mass of Carbon - Moles of Carbon = 24 g / 12 g/mol - Moles of Carbon = 2 moles

2. Calculate Moles of Oxygen: - Moles of Oxygen = Moles of Carbon - Moles of Oxygen = 2 moles

So, according to the stoichiometry of the balanced chemical equation, 2 moles of oxygen are required to completely combust 24 g of carbon.

Now, let's convert moles of oxygen to liters at standard temperature and pressure (STP) to see if 45 L of oxygen is sufficient.

The volume of 1 mole of any gas at STP is 22.4 L.

3. Calculate Volume of Oxygen: - Volume of Oxygen = Moles of Oxygen * 22.4 L/mol - Volume of Oxygen = 2 moles * 22.4 L/mol - Volume of Oxygen = 44.8 L

Based on this calculation, 45 L of oxygen is sufficient, with a small excess of 0.2 L.

Moving on to the next question:

Distinguishing Between Sodium Carbonate Solution and Sodium Hydroxide Solution:

To distinguish between a solution of sodium carbonate and a solution of sodium hydroxide, you can use a solution of hydrochloric acid (HCl). When hydrochloric acid is added to a solution of sodium carbonate, it will produce effervescence due to the release of carbon dioxide gas. On the other hand, when hydrochloric acid is added to a solution of sodium hydroxide, it will produce a neutralization reaction, resulting in the formation of water and a salt.

Therefore, to distinguish between the two solutions, you should use hydrochloric acid.

Moving on to the last question:

Sum of Coefficients in the Molecular Equation:

The balanced molecular equation for the reaction between barium hydroxide and sulfuric acid is:

Ba(OH)2(aq) + H2SO4(aq) → BaSO4(s) + 2H2O(l)

The sum of the coefficients in this balanced equation is: - 1 (coefficient of Ba(OH)2) + 1 (coefficient of H2SO4) + 1 (coefficient of BaSO4) + 2 (coefficient of H2O) = 5

Therefore, the sum of the coefficients in the molecular equation is 5.