Question

Найти количество вещества и число молекул 180г малахита

Answer 1

Mr(CuSO4*5H2O)=64+32+16*4+5*(1*2+16)=250 n=m/Mr=180/250=0,72моль Кол-во молекул 180/250×6,02*10^23=4,33*10^23

Answer 2

Finding the Amount of Substance and Number of Molecules in 180g of Malachite

To find the amount of substance and the number of molecules in 180g of malachite, we can use the molar mass of malachite and Avogadro's number.

Molar Mass of Malachite: The molar mass of malachite (Cu2CO3(OH)2) can be calculated by adding the atomic masses of its constituent elements.

The molar mass of Cu (copper) is 63.55 g/mol, C (carbon) is 12.01 g/mol, O (oxygen) is 16.00 g/mol, and H (hydrogen) is 1.01 g/mol.

Using the chemical formula of malachite, we can calculate its molar mass: 2(Cu) + C + 3(O) + 2(H) = 2(63.55) + 12.01 + 3(16.00) + 2(1.01) = 221.14 g/mol

Calculating the Amount of Substance: The amount of substance (in moles) can be calculated using the formula: \[ \text{Amount of substance} = \frac{\text{Mass}}{\text{Molar mass}} \]

Substituting the given mass of malachite (180g) and its molar mass (221.14 g/mol): \[ \text{Amount of substance} = \frac{180g}{221.14 \frac{g}{mol}} \]

\[ \text{Amount of substance} \approx 0.814 mol \]

Calculating the Number of Molecules: Avogadro's number states that 1 mole of any substance contains \(6.022 \times 10^{23}\) molecules.

Therefore, the number of molecules in 0.814 moles of malachite can be calculated as: \[ \text{Number of molecules} = \text{Amount of substance} \times 6.022 \times 10^{23} \]

\[ \text{Number of molecules} \approx 0.814 \times 6.022 \times 10^{23} \]

\[ \text{Number of molecules} \approx 4.89 \times 10^{23} \]

So, in 180g of malachite, there are approximately 0.814 moles of malachite and approximately \(4.89 \times 10^{23}\) molecules.

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