Question

Составьте электронной баланс 1) HNO3+Zn=N2+Zn(NO3)2+H2O 2)HNO3+Na=NH3+NaOH+H2O

Answer 1

H (+) N (5+) O3 (2-) + Zn (0) — N2 (0) + Zn (2+) (NO3)2 + H2 (+) O (2-)

2N (5+) +10ē — N2 (0) | окислитель
Zn (0) -2ē — Zn (2+) | восстановитель

Коэффициенты:

12HNO3 + 5Zn — 5Zn(NO3)2 + N2 + 6H2O

H (+) N (5+) O3 (2-) + Na (0) — N (3+) H3 (-) + Na (+) NO3 (-) + H2 (+) O (2-)

N (5+) +2ē — N (3+) | окислитель
Na (0) -1ē — Na (+) | восстановитель

Коэффициенты:

9HNO3 + 8Na — 8NaNO3 + NH3 + 3H2O

Answer 2

Электронные балансы для реакций:

1) HNO3 + Zn = N2 + Zn(NO3)2 + H2O 2) HNO3 + Na = NH3 + NaOH + H2O

1) HNO3 + Zn = N2 + Zn(NO3)2 + H2O:

The balanced electron-half equations for this reaction are as follows:

Oxidation half-reaction: Zn → Zn^2+ + 2e^- Reduction half-reaction: 2H^+ + 2e^- → H2

To balance the reaction, we need to multiply the oxidation half-reaction by 2 and the reduction half-reaction by 1:

2Zn + 4H^+ → 2Zn^2+ + 4e^- 2H^+ + 2e^- → H2

Now, we can add the two half-reactions together and cancel out the electrons:

2Zn + 4H^+ + 2H^+ + 2e^- → 2Zn^2+ + 4e^- + H2 2Zn + 6H^+ → 2Zn^2+ + H2

Finally, we can balance the hydrogen ions by adding 2HNO3 to the left side of the equation:

2HNO3 + 2Zn + 6H^+ → 2Zn^2+ + H2 + 2NO3^-

So, the balanced electron-half equation for the reaction is:

2HNO3 + 2Zn + 6H^+ → 2Zn^2+ + H2 + 2NO3^-

The balanced overall equation is:

2HNO3 + Zn → N2 + Zn(NO3)2 + H2O

.

2) HNO3 + Na = NH3 + NaOH + H2O:

The balanced electron-half equations for this reaction are as follows:

Oxidation half-reaction: 2H^+ + 2e^- → H2 Reduction half-reaction: Na → Na^+ + e^-

To balance the reaction, we need to multiply the oxidation half-reaction by 1 and the reduction half-reaction by 2:

2H^+ + 2e^- → H2 2Na → 2Na^+ + 2e^-

Now, we can add the two half-reactions together and cancel out the electrons:

2H^+ + 2e^- + 2Na → H2 + 2Na^+ + 2e^- 2H^+ + 2Na → H2 + 2Na^+

Finally, we can balance the hydrogen ions by adding 2HNO3 to the left side of the equation:

2HNO3 + 2H^+ + 2Na → H2 + 2Na^+ + 2NO3^-

So, the balanced electron-half equation for the reaction is:

2HNO3 + 2H^+ + 2Na → H2 + 2Na^+ + 2NO3^-

The balanced overall equation is:

2HNO3 + Na → NH3 + NaOH + H2O

.

I hope this helps! Let me know if you have any further questions.