Question

объясните тему степени окисления! 8 классс примерами

Answer 1

Ээх, надо слушать на уроке) Мы тоже эту тему проходим) 
Прочитай параграф, разберись) Тут долго объяснять)
В общем степень окисления определяется условно, как ионная, сколько электронов надо отдать или взять х.э. до заветной восьмерки %)

Answer 2

Understanding Oxidation States (Степени окисления)

In chemistry, oxidation state (степень окисления), also known as oxidation number, is a measure of the degree of oxidation of an atom in a chemical compound. It indicates the hypothetical charge that an atom would have if all bonds to atoms of different elements were 100% ionic. Here are some examples to illustrate the concept:

Examples of Oxidation States (Примеры степеней окисления)

1. Sulfur Dioxide (SO2): - In the reaction SO2 + 2HNO3 → H2SO4 + 2NO2, sulfur has an oxidation state of +4 and +6.

2. Carbon Monoxide (CO): - In the reaction SO2 + C → CO2 + S, carbon has an oxidation state of 0 and +2.

3. Hydrogen Peroxide (H2O2): - In the reaction 4H2O2 + PbS → PbSO4 + 4H2O, hydrogen has an oxidation state of +1 and 0.

4. Potassium Permanganate (KMnO4): - In the reaction 3H2O2 + 2KMnO4 → 3O2 + 2MnO2 + 2KOH + 2H2O, manganese has an oxidation state of +5 and +6.

5. Gold (Au): - In the reaction Au + HNO3 + 4HCl → HAuCl4 + NO + 2H2O, gold has an oxidation state of 0 and +3.

6. Sodium Carbonate (Na2CO3): - In the reaction Na2CO3 + 2CH3COOH → 2CH3COONa + H2O + CO2, carbon has an oxidation state of +4 and +2.

These examples demonstrate how different elements can have varying oxidation states in chemical reactions, highlighting the importance of understanding oxidation states in chemistry.

Conclusion (Заключение)

Understanding oxidation states is crucial in predicting the behavior of elements in chemical reactions and is fundamental to many aspects of chemistry, including redox reactions and the stability of chemical compounds.