Question

Определите массовую долю гидроксида натрия в растворе образующегося при сливпнии 100 г 40%го и 150 г 20%го растворов

Answer 1

Дано:
m₁(p-pa NaOH) = 100 г
ω₁(NaOH) = 40%=0.4
m₂(p-pa NaOH) = 150 г
ω₂(NaOH) = 20% = 0.2
Найти ω(NaOH)-?
m₁(NaOH) = m₁(p-pa NaOH)×ω₁(NaOH)
m₁(NaOH) = 100 г×0,4 = 40 г
m₂(NaOH) = 150 г×0,2 = 30 г
m(NaOH) = m₁(NaOH) + m₂(NaOH)
m(NaOH) = 40 г + 30 г = 70 г
m(p-pa NaOH) = m₁(p-pa NaOH) + m₂(p-pa NaOH)
m(p-pa NaOH) = 100 г + 150 г = 250 г
ω(NaOH)=m(NaOH)/m(p-pa NaOH) 
ω(NaOH) = 70 г/250 г = 0,28 или 28%
Ответ: 28%

Answer 2

W%=m(Вещества) /m(Раствора) *100%
m(Вещества)=W%*m(Раствора) /100%
m(NaOH)1=100г*40%/100%=40г
m(NaOH) 2=150г*20%/100%= 30г
m(NaOH) всего растворенного=40г+30г=70г
m(NaOH) всего раствора= 100г+150г=250г
W%=70г/250г*100%=28%
Вроде все

Answer 3

Calculation of the Mass Fraction of Sodium Hydroxide in the Solution

To determine the mass fraction of sodium hydroxide (NaOH) in the solution formed by mixing 100 g of a 40% solution and 150 g of a 20% solution, we need to consider the amount of NaOH present in each solution.

Let's start by calculating the amount of NaOH in the 40% solution:

Mass of NaOH in the 40% solution = 40% of 100 g = 40 g.

Next, let's calculate the amount of NaOH in the 20% solution:

Mass of NaOH in the 20% solution = 20% of 150 g = 30 g.

Now, we can calculate the total mass of NaOH in the solution by adding the amounts from both solutions:

Total mass of NaOH = 40 g + 30 g = 70 g.

To find the mass fraction of NaOH in the solution, we divide the total mass of NaOH by the total mass of the solution:

Mass fraction of NaOH = (70 g / (100 g + 150 g)) * 100% = (70 g / 250 g) * 100% = 28%.

Therefore, the mass fraction of sodium hydroxide in the solution formed by mixing 100 g of a 40% solution and 150 g of a 20% solution is 28%.