Question

Какой объем 15%-ного раствора хлороводорода плотностью 1,075 г/мЛ пойдет на полную нейтрализацию гидроксида кальция, образовавшегося при гидролизе карбида кальция, если при гидролизе выделилось 17,92 л (н.у.) газа?

Answer 1

В вложении. неаккуратно но, надеюсь, верно

Answer 2

Cu2O; Fe2O3; WO3; FeO; CO2; SO3; SnO2; Mn2O7

Answer 3

Calculation of the Volume of 15% Hydrochloric Acid Solution

To calculate the volume of a 15% hydrochloric acid solution required for the complete neutralization of calcium hydroxide, we need to consider the balanced chemical equation for the reaction between hydrochloric acid and calcium hydroxide.

The balanced equation for the reaction is as follows: ``` 2HCl + Ca(OH)2 -> CaCl2 + 2H2O ```

From the equation, we can see that 2 moles of hydrochloric acid react with 1 mole of calcium hydroxide to produce 1 mole of calcium chloride and 2 moles of water.

Given that 17.92 liters of gas (at standard temperature and pressure) were evolved during the hydrolysis of calcium carbide, we can assume that the gas evolved is hydrogen gas (H2). This means that 1 mole of calcium carbide reacts to produce 1 mole of hydrogen gas.

To determine the volume of the 15% hydrochloric acid solution required, we need to calculate the number of moles of calcium hydroxide and hydrochloric acid involved in the reaction.

Calculation Steps:

Step 1: Calculate the number of moles of hydrogen gas evolved. - The volume of gas evolved is given as 17.92 liters. - Since 1 mole of calcium carbide reacts to produce 1 mole of hydrogen gas, the number of moles of hydrogen gas evolved is also 17.92 moles.

Step 2: Calculate the number of moles of calcium hydroxide. - From the balanced equation, we know that 2 moles of hydrochloric acid react with 1 mole of calcium hydroxide. - Therefore, the number of moles of calcium hydroxide is half the number of moles of hydrogen gas evolved, which is 17.92/2 = 8.96 moles.

Step 3: Calculate the volume of the 15% hydrochloric acid solution. - The concentration of the hydrochloric acid solution is given as 15%. - This means that 100 mL of the solution contains 15 grams of hydrochloric acid. - The density of the solution is given as 1.075 g/mL. - Using the density, we can calculate the mass of the solution required to obtain 8.96 moles of hydrochloric acid.

Let's calculate the volume of the 15% hydrochloric acid solution required for the complete neutralization of calcium hydroxide.

Calculation:

1. Calculate the mass of hydrochloric acid required: - The molar mass of hydrochloric acid (HCl) is 36.46 g/mol. - The number of moles of hydrochloric acid required is 8.96 moles. - Therefore, the mass of hydrochloric acid required is 8.96 moles * 36.46 g/mol = 326.0416 g.

2. Calculate the volume of the 15% hydrochloric acid solution required: - The density of the solution is given as 1.075 g/mL. - Let's assume the volume of the solution required is V mL. - The mass of the solution required is equal to the mass of hydrochloric acid required. - Therefore, 326.0416 g = V mL * 1.075 g/mL. - Solving for V, we get V = 326.0416 g / 1.075 g/mL ≈ 303.5 mL.

Therefore, approximately 303.5 mL of the 15% hydrochloric acid solution with a density of 1.075 g/mL would be required for the complete neutralization of the calcium hydroxide formed during the hydrolysis of calcium carbide, given that 17.92 liters of gas (at standard temperature and pressure) were evolved.

Please note that this calculation assumes ideal conditions and does not account for any losses during the reaction or other factors that may affect the actual volume required.