Question

Помогите, пожалуйста! Через 80 г раствора с массовой долей гидроксида натрия 12% пропустили углекислый газ до образования карбоната натрия. Вычислите объем при н.у. вступившего в реакцию газа.

Answer 1

ДаНО:
w(р-ра NaOH) = 12% 
m(р-ра NaOH) = 80 г 
найти: V(CO2) 
Решение: 
m(р.в-ва) = m(р-ра) ∙ w(р-ра) \ 100% 
m(NaOH) = 80 г ∙ 12%\ 100% = 9,6 г 
 х л         9,6 г                          
CO2 + 2NaOH = Na2CO3 + H2O 
22,4 л      80 г   
                       
х л ----- 9,6 г 
22,4 л ----- 80 г 
х = 9,6 г ∙ 22,4 л\80 г = 2,688 л 
Ответ:  V(СО2) =  2,688 л

Answer 2

Calculation of Gas Volume

To calculate the volume of gas that reacted, we need to determine the number of moles of the gas and then use the ideal gas law to calculate the volume.

Given: - Mass fraction of sodium hydroxide (NaOH) in the solution: 12% - The gas reacted with the sodium hydroxide to form sodium carbonate (Na2CO3)

To calculate the number of moles of the gas, we can use the concept of stoichiometry. The balanced chemical equation for the reaction between sodium hydroxide and carbon dioxide (CO2) is:

2 NaOH + CO2 -> Na2CO3 + H2O

From the equation, we can see that 2 moles of NaOH react with 1 mole of CO2 to produce 1 mole of Na2CO3. Therefore, the number of moles of CO2 can be calculated as follows:

Number of moles of CO2 = (Mass of NaOH / Molar mass of NaOH) * (1 mole CO2 / 2 moles NaOH)

To find the mass of NaOH, we need to know the total mass of the solution. Unfortunately, the total mass of the solution is not provided in the question. Therefore, we cannot calculate the exact number of moles of CO2 and, consequently, the volume of the gas.

However, if you provide the total mass of the solution, I can help you calculate the volume of the gas using the ideal gas law.

Please let me know if you have any additional information or if there's anything else I can assist you with.