Question

Уважаемые, помогите пожалуйста. Объясните, как находить степень окисления хрома в таком соединении (NH4)2CrO4Как считать? Алгоритм действий. Не понимаю.

Answer 1

Если не ошибаюсь, то степень окисления хрома в данной соединении +6

Answer 2

Начнем с кислорода. У него СО -2, а таких кислородов 4, значит, -8. У аммония NH4 степень окисления +1, а их два, значит, +2. Но в молекуле сумма плюсов и минусов равна нулю. Чтобы уравнять 8 минусов, надо 8 плюсов, 2 из них есть, значит остальное на Хром. Его Степень Окисления +6.

Answer 3

Finding the Oxidation State of Chromium in (NH4)2CrO4

To determine the oxidation state of chromium (Cr) in the compound (NH4)2CrO4, you can follow these steps:

1. Identify the known oxidation states of the other elements in the compound. In this case, we have ammonium (NH4+) and oxygen (O2-). The oxidation state of ammonium is +1, and the oxidation state of oxygen is -2.

2. Assign variables to the unknown oxidation states. Let's assume the oxidation state of nitrogen (N) in ammonium is x, and the oxidation state of chromium (Cr) is y.

3. Use the known oxidation states and the overall charge of the compound to set up an equation. In this case, the compound has a neutral charge, so the sum of the oxidation states must equal zero.

(NH4)2CrO4: (NH4+)2 + Cr + 4(O2-) = 0

4. Solve the equation for the unknown oxidation state of chromium (Cr). Start by substituting the known oxidation states:

2(+1) + y + 4(-2) = 0

Simplifying the equation:

2 + y - 8 = 0

y - 6 = 0

y = +6

Therefore, the oxidation state of chromium (Cr) in (NH4)2CrO4 is +6.

Please note that this method assumes that the compound is neutral and does not take into account any complex or coordination effects that may affect the oxidation state of chromium.