Question

Напишите уравнения при помощи которых можно осуществить эти превращенияа) CH4 ⇒ C2H2 ⇒C6H6 ⇒ C6H5Clб) CaCO3 ⇒CaC2 ⇒ C2H2 ⇒C2H4 ⇒C2H5Cl ⇒ бутенв) CH4 ⇒ C2H6 ⇒ C3H8 ⇒ C6H14 ⇒ C6H6 ⇒ C6H5NO2

Answer 1

CaCO3=CaO+CO2
CaO+3C=CaC2+CO
CaC2+2H2O=C2H2+Ca(OH)2
C2H2+H2=C2H4
C2H4+HCL=C2H5CL
2C2H5CL+2Na=C4H10+2NaCL
C4H10=C2H8+H2
           бутен

Answer 2

A)2CH4=C2H2 + H2
3C2H2=C6H6
C6H6+CL2=C6H5+HCL

Answer 3

Equations for the Given Transformations:

a) CH4 ⇒ C2H2 ⇒ C6H6 ⇒ C6H5Cl: - The transformation from CH4 to C2H2 involves the removal of three hydrogen atoms from methane to form a triple bond between two carbon atoms [[1]]. - The transformation from C2H2 to C6H6 involves the addition of three hydrogen atoms to the triple bond of acetylene to form a benzene ring [[2]]. - The transformation from C6H6 to C6H5Cl involves the substitution of one hydrogen atom in benzene with a chlorine atom [[3]].

b) CaCO3 ⇒ CaC2 ⇒ C2H2 ⇒ C2H4 ⇒ C2H5Cl: - The transformation from CaCO3 to CaC2 involves the heating of calcium carbonate to produce calcium carbide [[4]]. - The transformation from CaC2 to C2H2 involves the reaction of calcium carbide with water to produce acetylene gas [[5]]. - The transformation from C2H2 to C2H4 involves the reaction of acetylene with hydrogen to form ethylene [[6]]. - The transformation from C2H4 to C2H5Cl involves the substitution of a hydrogen atom in ethylene with a chlorine atom [[7]].

c) CH4 ⇒ C2H6 ⇒ C3H8 ⇒ C6H14 ⇒ C6H6 ⇒ C6H5NO2: - The transformation from CH4 to C2H6 involves the addition of one hydrogen atom to methane to form ethane [[8]]. - The transformation from C2H6 to C3H8 involves the addition of one more hydrogen atom to ethane to form propane [[9]]. - The transformation from C3H8 to C6H14 involves the addition of three more hydrogen atoms to propane to form hexane [[10]]. - The transformation from C6H14 to C6H6 involves the removal of three hydrogen atoms from hexane to form a benzene ring [[11]]. - The transformation from C6H6 to C6H5NO2 involves the substitution of one hydrogen atom in benzene with a nitro group (-NO2) [[12]].

I hope this helps! Let me know if you have any further questions.