Question

Объемная доля азота в газовой смеси 40 % кислорода 60% определите плотность смеси по водороду

Answer 1

1. Найдем молярную массу смеси:
М(см)=0,4*М(N2)+0,6*М(O2)=0,4*28+0,6*32=30,4 г/моль
2. Dсм(Н2)=М(см)/М(Н2)=30,4/2=15,2

Answer 2

Calculation of Gas Mixture Density

To determine the density of a gas mixture, we need to know the volume fraction of each component and the density of each component. In this case, we are given that the gas mixture consists of 40% nitrogen and 60% oxygen, and we need to determine the density of the mixture using hydrogen as a reference.

Unfortunately, the search results provided do not directly provide the density of the gas mixture. However, we can make an estimation based on the densities of the individual gases and their volume fractions.

According to the Ideal Gas Law, the density of a gas is directly proportional to its molar mass. The molar mass of nitrogen (N2) is approximately 28 g/mol, and the molar mass of oxygen (O2) is approximately