Question

Расстановка коэфициентов в Окислительно-восстановительных реакциях. Сделайте пожалуйста хотя бы 5 реакций буду очень благодарна.1. Cl2 + H2S + H2O → H2SO4 + HCl2. Cl2 + KI + H2O → HCl + KIO33. Cl2 + I2 + H2O → HCl + HIO34. FeSO4 + HIO3 + H2SO4 → I2↓ + Fe2(SO4)3 + HBr5. NH3 + KMnO4 + KOH → N2↑ + K2MnO4 + H2O6. MnSO4 + H2O2 + NaOH → MnO2↓ + Na2SO4 + H2O7. H2O2 + KI → I2 + KOH8. F2 + NaOH → NaF + OF2↑ + H2O9. KI + KBrO3 + HCl → I2↓ + KBr + KCl + H2O10. KBr + KMnO4 + H2SO4 → Br2↓ + MnSO4 + K2SO4 + H2O

Answer 1

Все дорешала), сейчас еще 4 цепочку попробую, подберу продукты

Answer 2

2Cl2+H2S+4H2O=H2SO4+4HCl
3Cl2+KI+3H2O=6HCl+KIO3
5Cl2+I2+6H2O=10HCl+2HIO3
10FeSO4+2HIO3+5H2SO4=I2+5Fe2(SO4)3+6H2O
NH3+8KMnO4+9KOH=N2+8K2MnO4+6H2O
MnSO4+H2O2+2NaOH=MnO2+Na2SO4+2H2O
H2O2+2KI=I2+2KOH
2F2+2NaOH=2NaF+OF2+H2O
6KI+KBrO3+6HCl=3I2+KBr+6KCl+3H2O
10KBr+2KMnO4+8H2SO4=5Br2+2MnSO4+6K2SO4+8H2O

Answer 3

Oxidation-Reduction Reactions and Coefficient Placement

In oxidation-reduction (redox) reactions, there is a transfer of electrons between species. Oxidation refers to the loss of electrons, while reduction refers to the gain of electrons. To balance redox reactions, it is important to assign oxidation numbers to each element and then balance the equation by placing coefficients in front of the reactants and products.

Here are five examples of oxidation-reduction reactions with coefficients placed:

1. Cl2 + H2S + H2O → H2SO4 + HCl: - In this reaction, chlorine (Cl2) is reduced from an oxidation state of 0 to -1 in HCl, while sulfur (S) is oxidized from -2 in H2S to +6 in H2SO4 [[1]].