Question

Для полного гидролиза 1,76 г сложного эфира одноосновной карбоновой кислоты и одноатомного спирта потребовалось 0,02 моль NaOH. определите молекулярную массу эфира и его молекулярную формулу

Answer 1

Н эфира = н щёлочи = 0,02 моль,
т.е. М (эфира) = 1,76:0,02 = 88 г/моль
Общая формула сложного эфира RCOOR'
То есть на массу двух радикалов приходится 88 - 44 = 44 г/моль, т.е. суммарный состав двух радикалов - 3 атома С и 8 атомов Н.
Молекулярная формула эфира С4Н8О2. Этой формуле может соответствовать 4 структуры, но для точного определения имеющихся данных недостаточно.

Answer 2

Calculation of Molecular Mass and Formula of the Ether

To determine the molecular mass and formula of the ether, we need to use the information provided about the hydrolysis reaction.

According to the given information, 1.76 g of a complex ether (composed of a monocarboxylic acid and a monatomic alcohol) required 0.02 mol of NaOH for complete hydrolysis.

To calculate the molecular mass of the ether, we can use the equation:

Molecular mass (g/mol) = Mass of the ether (g) / Number of moles of the ether (mol)

From the given information, we know that the mass of the ether is 1.76 g and the number of moles of NaOH used is 0.02 mol. However, we need to determine the number of moles of the ether.

To do this, we can use the stoichiometry of the reaction. Since 1 mole of NaOH reacts with 1 mole of the ether, the number of moles of the ether is also 0.02 mol.

Now we can calculate the molecular mass of the ether:

Molecular mass = 1.76 g / 0.02 mol

Let's calculate the molecular mass using the given values:

Molecular mass = 1.76 g / 0.02 mol = 88 g/mol

Therefore, the molecular mass of the ether is 88 g/mol.

To determine the molecular formula of the ether, we need to know the molecular masses of the monocarboxylic acid and the monatomic alcohol. Unfortunately, the specific compounds involved in the reaction are not provided, so we cannot determine the exact molecular formula of the ether.

Please provide additional information about the monocarboxylic acid and monatomic alcohol involved in the reaction to determine the molecular formula of the ether.