Question

написать молекулярное и ионное уравнение раствора сульфата алюминия с раствором хлорида бария

Answer 1

Al(SO4)3+ 3BaCl=Al(cl)3+3BaSO4

Answer 2

Molecular and Ionic Equations for the Reaction of Aluminum Sulfate with Barium Chloride

When aluminum sulfate reacts with barium chloride, a double displacement reaction occurs, resulting in the formation of aluminum chloride and barium sulfate. Let's break down the molecular and ionic equations for this reaction.

Molecular Equation:

The molecular equation for the reaction is as follows: Al2(SO4)3 + 3BaCl2 → 2AlCl3 + 3BaSO4

Ionic Equation:

The ionic equation for the reaction can be represented as: Al^3+ + 3SO4^2- + 3Ba^2+ + 6Cl^- → 2Al^3+ + 6Cl^- + 3BaSO4

The above equations represent the reaction between aluminum sulfate and barium chloride, resulting in the formation of aluminum chloride and barium sulfate.

I hope this helps! If you have any further questions or need additional information, feel free to ask.