Question

РЕБЯТА!ГОРИТГОРИТГОРИТ!!!К 550,00 мл 0,1925 н. раствора HCl прибавили 50,00 мл раствора HCl с титром 0,02370. Вычислить нормальность и титр полученного раствора.

Answer 1

Обозначим искомый раствор, как третий:)
Мэ(HCl) = 36.5 г/моль
m₁ = Cн₁ * Мэ* V₁
m₂ = Cн₂ * Мэ* V₂
m₃ = Cн₃ * Мэ* V₃
V3 = V1 + V2,  m₃ = Мэ*(Cн₁* V₁ + Cн₂* V₂)
T = [Мэ*Сн]/1000, отсюда Сн₂ = T*1000/Мэ = 0,02370*1000/36,5 = 0,6493н.
Cн₃ = [Мэ*(Cн₁* V₁ + Cн₂* V₂)] / [Мэ*(V₁ + V₂)], сократив Мэ получим
Cн₃ = [Cн₁* V₁ + Cн₂* V₂] / [V₁ + V₂] = [550,00*0,1925 + 50,00*0,6493]/ (550,00 + 50,00) = 
=0,2306н.
T = [Мэ*Сн]/1000 = 36,5 * 0,2306/1000 = 0,00842 г/мл
Ответ: Cн₃=0,2306н.,  T = 0,00842 г/мл

Answer 2

Calculation of Normality and Titer of the Solution

To calculate the normality and titer of the resulting solution, we need to consider the volumes and concentrations of the initial solutions.

Given: - Volume of the first solution (V1) = 550.00 mL - Normality of the first solution (N1) = 0.1925 N - Volume of the second solution (V2) = 50.00 mL - Titer of the second solution (T2) = 0.02370

To calculate the normality (N) of the resulting solution, we can use the following formula:

N = (N1 * V1 + N2 * V2) / (V1 + V2)

Substituting the given values:

N = (0.1925 N * 550.00 mL + N2 * 50.00 mL) / (550.00 mL + 50.00 mL)

To calculate the titer (T) of the resulting solution, we can use the following formula:

T = (N1 * V1 * T1 + N2 * V2 * T2) / (N * V)

Substituting the given values:

T = (0.1925 N * 550.00 mL * 0.02370 + N2 * 50.00 mL * 0.02370) / ((0.1925 N * 550.00 mL + N2 * 50.00 mL) / (550.00 mL + 50.00 mL))

Please note that the value of N2 is not provided in the given information. Without the value of N2, it is not possible to calculate the exact normality and titer of the resulting solution.