Question

Уравнять с помощью электронного баланса: 1. Fe+O2=Fe2O32. Zn+O2=ZnO3. HNO3=HNO2+O2

Answer 1

1).4Fe+3O2=2Fe2O3
2.)2Zn+O2=2ZnO
3)2HNO3=2HNO2+O2

Answer 2

1. 4Fe+3O2=2Fe2O3
восстановитель Fe(0) - 3=Fe( +3)  4 окисление
окислитель  O2 (0) + 4= 2O (-2) 3 восстановление

2. 2Zn+O2=2Zn

восстановитель Zn(0) - 2=Fe( +2)  4 2 окисление
окислитель  O2 (0) + 4= 2O (-2) 2 1 восстановление

3. 2HNO3=2HNO2+O2
восстановительN(+5) - 2=N( +3)  4 2 окисление
окислитель  O2 (0) + 4= 2O (-2) 2 1 восстановление

Answer 3

Balancing Chemical Equations:

To balance chemical equations using an electronic balance, you need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's balance the given equations:

1. Fe + O2 = Fe2O3: - To balance the equation, we need to have an equal number of Fe atoms on both sides. We can achieve this by placing a coefficient of 2 in front of Fe on the left side: 2Fe + O2 = Fe2O3 - Now, let's balance the oxygen atoms. There are 2 oxygen atoms on the left side and 3 oxygen atoms on the right side. To balance them, we can place a coefficient of 3/2 in front of O2 on the left side: 2Fe + (3/2)O2 = Fe2O3

2. Zn + O2 = ZnO: - To balance the equation, we need to have an equal number of Zn atoms on both sides. We can achieve this by placing a coefficient of 2 in front of Zn on the left side: 2Zn + O2 = ZnO - The oxygen atoms are already balanced with 2 on both sides, so no further changes are needed.

3. HNO3 = HNO2 + O2: - To balance the equation, we need to have an equal number of nitrogen atoms on both sides. We can achieve this by placing a coefficient of 2 in front of HNO2 on the right side: HNO3 = 2HNO2 + O2 - The oxygen atoms are already balanced with 3 on both sides, so no further changes are needed.

Please note that the coefficients in front of the chemical formulas represent the number of molecules or moles of each substance involved in the reaction. Balancing equations is an essential step in understanding chemical reactions and ensuring the conservation of mass.

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