Question

Составить распределение электронов по уровням в атомах F Al, Be, Ar

Answer 1

F 2,7
Al 2,8,3
Be 2,2
Ar 2,8,8

Answer 2

Raspravleniye Elektronov (Electron Distribution) in Atoms of F, Al, Be, Ar

Let's break down the electron distribution in the atoms of Fluorine (F), Aluminum (Al), Beryllium (Be), and Argon (Ar) based on the provided information.

1. Fluorine (F) Atom: - The electron configuration of Fluorine is 1s^2 2s^2 2p^5. - This means that Fluorine has 9 electrons distributed as follows: - 1s^2 (2 electrons) - 2s^2 (2 electrons) - 2p^5 (5 electrons).

2. Aluminum (Al) Atom: - The electron configuration of Aluminum is 1s^2 2s^2 2p^6 3s^2 3p^1. - This means that Aluminum has 13 electrons distributed as follows: - 1s^2 (2 electrons) - 2s^2 (2 electrons) - 2p^6 (6 electrons) - 3s^2 (2 electrons) - 3p^1 (1 electron).

3. Beryllium (Be) Atom: - The electron configuration of Beryllium is 1s^2 2s^2. - This means that Beryllium has 4 electrons distributed as follows: - 1s^2 (2 electrons) - 2s^2 (2 electrons).

4. Argon (Ar) Atom: - The electron configuration of Argon is 1s^2 2s^2 2p^6 3s^2 3p^6. - This means that Argon has 18 electrons distributed as follows: - 1s^2 (2 electrons) - 2s^2 (2 electrons) - 2p^6 (6 electrons) - 3s^2 (2 electrons) - 3p^6 (6 electrons).

In summary, the electron distribution in the atoms of F, Al, Be, and Ar is as follows: - Fluorine (F): 2-7 - Aluminum (Al): 2-8-3 - Beryllium (Be): 2-2 - Argon (Ar): 2-8-8