Question

Рассчитайте массу магния для образования массой 6 грамм его оксида

Answer 1

   ₓ               ₆
2Mg+O₂=2MgO
  ⁴⁸              80

1)M(Mg)=24
2)M(MgO)=40
3)m(Mg)=(6*48)/80=3,6(г)
Ответ: 3,6 г

Answer 2

Calculating the Mass of Magnesium Oxide

To calculate the mass of magnesium required to form an oxide with a mass of 6 grams, we can use the chemical equation for the formation of magnesium oxide and the molar masses of the elements involved.

The chemical equation for the formation of magnesium oxide is: Mg + O2 → MgO

The molar mass of magnesium (Mg) is 24.305 g/mol, and the molar mass of oxygen (O) is 16.00 g/mol.

Using this information, we can calculate the mass of magnesium required.

According to the chemical equation, 1 mole of magnesium reacts with 1 mole of oxygen to produce 1 mole of magnesium oxide.

Using the molar masses of magnesium and oxygen, we can calculate the molar mass of magnesium oxide: Mg: 24.305 g/mol O: 16.00 g/mol MgO: 24.305 g/mol + 16.00 g/mol = 40.305 g/mol

Now, we can calculate the mass of magnesium required to form 6 grams of magnesium oxide.

Using the formula: n = m/M where: - n = number of moles - m = mass - M = molar mass

We can rearrange the formula to solve for the mass: m = n * M

Substituting the values: n = 6 g / 40.305 g/mol n ≈ 0.149 moles

Now, we can calculate the mass of magnesium required: m = n * M m ≈ 0.149 moles * 24.305 g/mol m ≈ 3.62 grams

Therefore, the mass of magnesium required to form a 6-gram mass of magnesium oxide is approximately 3.62 grams.

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