Question

Найти объем аммиака, который образуется при взаимодействии азота объемом 8л и водорода объемом 10л.

Answer 1

3H2+N2=2NH3

n(H2)=10/22.4=0,446 моль 
n(N2)=8/22.4=0,357 моль 
получается что водород в недостатке, а азот в избытке 
дальнейшие расчеты проводим по водороду 
n(NH3)=0.446*1.5=0.669 моль 
V(NH3)=n*Vm=0,669*22,4=14,9856=15л 

Ответ: 15 л 

Answer 2

Calculating the Volume of Ammonia Produced

To find the volume of ammonia produced when nitrogen with a volume of 8 liters and hydrogen with a volume of 10 liters react, we can use the balanced chemical equation for the formation of ammonia from nitrogen and hydrogen:

N2 + 3H2 → 2NH3

According to the balanced chemical equation, 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia. From the given volumes, we can calculate the amount of each gas in moles using the ideal gas law.

Calculating Moles of Nitrogen and Hydrogen

Using the ideal gas law equation:

PV = nRT

Where: - P = pressure (assumed constant) - V = volume - n = number of moles - R = ideal gas constant - T = temperature (assumed constant)

We can rearrange the equation to solve for the number of moles:

n = PV / RT

Given: - Volume of nitrogen (V1) = 8 liters - Volume of hydrogen (V2) = 10 liters - Assuming constant pressure (P) and temperature (T)

We can calculate the number of moles of nitrogen and hydrogen using the ideal gas constant (R).

Calculating the Volume of Ammonia Produced

Using the stoichiometry of the balanced chemical equation, we can determine the limiting reactant and the amount of ammonia produced.

Since the balanced chemical equation shows that 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia, we can use the mole ratio to determine the limiting reactant and the amount of ammonia produced.

Finally, we can use the ideal gas law to calculate the volume of ammonia produced from the moles of ammonia.

Let's calculate the volume of ammonia produced based on the given information and the above steps.