Question

Расчитайте объем водорода присоединившегося к 68,8л ацетилена до образования этана потерями принебречь. Спасибо)

Answer 1

68,8 л Х л
CH=-CH. + 2H2. -> CH3-CH3
n=1 моль. n=2 моль
Vm=22,4 л/моль. Vm=22 ,4 л/ моль
V=22,4 л V=44,8 л

68,8 л С2Н2. - Х л Н2
22,4 л С2Н2. - 44,8 л Н2
V(H2) = 68,8 * 44,8 / 22,4 = 137,6 л

Answer 2

Calculating the Volume of Hydrogen Joined to 68.8L of Acetylene to Form Ethane

To calculate the volume of hydrogen that has joined to 68.8L of acetylene to form ethane, we can use the balanced chemical equation for the reaction between acetylene (C2H2) and hydrogen (H2) to form ethane (C2H6):

C2H2 + 2H2 → C2H6

According to the balanced chemical equation, 1 mole of acetylene reacts with 2 moles of hydrogen to produce 1 mole of ethane.

Given that the volume of acetylene is 68.8L, we need to calculate the volume of hydrogen that has joined to the acetylene to form ethane.

Using the concept of molar volume at standard temperature and pressure (STP), which is 22.4L/mol, we can calculate the volume of hydrogen required.

Calculation:

1. Calculate the moles of acetylene: - Moles of acetylene = Volume of acetylene / Molar volume at STP - Moles of acetylene = 68.8L / 22.4L/mol

2. Calculate the moles of hydrogen required: - According to the balanced chemical equation, 1 mole of acetylene reacts with 2 moles of hydrogen. - Moles of hydrogen = 2 * Moles of acetylene

3. Calculate the volume of hydrogen: - Volume of hydrogen = Moles of hydrogen * Molar volume at STP

Let's calculate the volume of hydrogen that has joined to the acetylene to form ethane using the above steps.

Result:

- Moles of acetylene = 68.8L / 22.4L/mol = 3.071 moles - Moles of hydrogen = 2 * 3.071 = 6.142 moles - Volume of hydrogen = 6.142 moles * 22.4L/mol = 137.6L

The volume of hydrogen that has joined to 68.8L of acetylene to form ethane is approximately 137.6 liters.

I hope this helps! If you have any further questions, feel free to ask.