Question

Li+h2o Na+ h2o K+h2o Rb+h2o Cs+h2o И 3 электронных баланса

Answer 1

Na+ h2o= Na OH + H2
K+h2o  = 2КОН+H2
Rb+h2o=2RbОН+H2
Cs+h2o=2CsОН+H2

Answer 2

Chemical Reactions and Electron Balances

When Li, Na, K, Rb, and Cs react with water, they form hydroxides and release hydrogen gas. The general equation for these reactions is:

Li + H2O → LiOH + H2 Na + H2O → NaOH + H2 K + H2O → KOH + H2 Rb + H2O → RbOH + H2 Cs + H2O → CsOH + H2 In these reactions, the metals (Li, Na, K, Rb, Cs) react with water to form the corresponding metal hydroxide and hydrogen gas. The electron balances for these reactions can be determined by examining the oxidation states of the elements involved.

The oxidation state of hydrogen in water is +1, and the oxidation state of the metal in the hydroxide is +1. Therefore, the electron balance for these reactions can be summarized as follows:

Li: 0 → +1 Na: 0 → +1 K: 0 → +1 Rb: 0 → +1 Cs: 0 → +1 This indicates that the metals (Li, Na, K, Rb, Cs) undergo a reduction reaction, where their oxidation state increases from 0 to +1, while hydrogen undergoes an oxidation reaction, where its oxidation state decreases from +1 to 0.

These reactions demonstrate the reactivity of alkali metals with water, leading to the formation of metal hydroxides and the release of hydrogen gas.

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