Question

Pb(NO3)2+K2S-> напешите молекулярную ионную реакцию и полное ионное, и сокрашенное ионное .спасибо

Answer 1

$Pb(NO3)2 + K2S = PbS + 2KNO3$
Pb(+2) + 2NO3(-) + 2K(+) + S(-2) → PbS + 2K(+) + 2NO3(-)
Pb(+2) + S(-2) → PbS

Answer 2

Molecular and Ionic Reactions for Pb(NO3)2 + K2S

Molecular Reaction: The molecular equation for the reaction between lead(II) nitrate (Pb(NO3)2) and potassium sulfide (K2S) is as follows: Pb(NO3)2 + K2S → PbS + 2KNO3

Ionic Equation: The ionic equation for the reaction can be represented as: Pb^2+ + 2NO3^- + 2K^+ + S^2- → PbS + 2K^+ + 2NO3^-

Complete Ionic Equation: Breaking down the ionic compounds into their respective ions, the complete ionic equation is: Pb^2+ + 2NO3^- + 2K^+ + S^2- → PbS + 2K^+ + 2NO3^-

Net Ionic Equation: The net ionic equation, which excludes the spectator ions (ions that appear on both sides of the equation), is: Pb^2+ + S^2- → PbS

This reaction involves the formation of lead(II) sulfide (PbS) and potassium nitrate (KNO3) as the products.

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