Question

В реакции цинка с соляной кислотой образовалась 68 грамм хлорида цинка.Рассчитайте массу и количество вещества цинка,вступившего в реакцию.

Answer 1

 M(Zn)=65

M(ZnCl2)=136

 

x г                      68 г

Zn + 2HCl => ZnCl2 + H2

65 г                    136 г

 

65:x = 136:68

х= 32,5 г

n(Zn)=m/M= 32,5/65=0,5  моль

 

Answer 2

Calculation of Zinc Mass and Moles

To calculate the mass and number of moles of zinc that reacted with hydrochloric acid, we need to use the given information that 68 grams of zinc chloride were formed.

The balanced chemical equation for the reaction between zinc and hydrochloric acid is:

Zn + 2HCl → ZnCl2 + H2

From the equation, we can see that one mole of zinc reacts with two moles of hydrochloric acid to produce one mole of zinc chloride.

To calculate the mass of zinc that reacted, we can use the molar mass of zinc, which is approximately 65.38 g/mol.

Let's calculate the mass and number of moles of zinc:

1. Calculate the number of moles of zinc chloride formed: - The molar mass of zinc chloride (ZnCl2) is approximately 136.29 g/mol. - Using the formula: moles = mass / molar mass, we can calculate the number of moles of zinc chloride: - Moles of zinc chloride = 68 g / 136.29 g/mol = 0.4989 mol

2. Calculate the number of moles of zinc: - From the balanced equation, we know that one mole of zinc reacts to form one mole of zinc chloride. - Therefore, the number of moles of zinc is also 0.4989 mol.

3. Calculate the mass of zinc: - Using the formula: mass = moles * molar mass, we can calculate the mass of zinc: - Mass of zinc = 0.4989 mol * 65.38 g/mol = 32.63 g

Therefore, the mass of zinc that reacted with hydrochloric acid is approximately 32.63 grams, and the number of moles of zinc is approximately 0.4989 moles.