Question

Химия 8 класс. Расчёт по химическим уровнениям . Помогите пожалуйста ! вычислить массу оксида меди,которая образуется при реакции 64г меди с кислородом.

Answer 1

64г                       х г
2Cu     +   O2=2CuO ;
128г/моль       160г/моль

Найдём Х через пропорцию:
х г=64*160/128=80 грамм.

Ответ: 80 грамм.

Answer 2

Calculating the Mass of Copper Oxide

To calculate the mass of copper oxide formed when 64g of copper reacts with oxygen, we can use the chemical equation for the reaction between copper and oxygen to form copper oxide. The balanced chemical equation for this reaction is:

2Cu + O2 → 2CuO

According to this equation, 2 moles of copper react with 1 mole of oxygen to produce 2 moles of copper oxide.

To calculate the mass of copper oxide formed, we can use the following steps:

1. Calculate the molar mass of copper (Cu) and oxygen (O). 2. Use the molar ratio from the balanced chemical equation to find the moles of copper oxide formed. 3. Convert the moles of copper oxide to grams to find the mass.

Step 1: Calculate the Molar Mass

The molar mass of an element is the mass of one mole of atoms of that element. The molar mass of copper (Cu) is approximately 63.55 g/mol, and the molar mass of oxygen (O) is approximately 16.00 g/mol.

Step 2: Use the Molar Ratio

According to the balanced chemical equation, 2 moles of copper react with 1 mole of oxygen to produce 2 moles of copper oxide. This means that the molar ratio of copper to copper oxide is 2:2, or simply 1:1.

Step 3: Calculate the Mass of Copper Oxide

Now, we can calculate the mass of copper oxide formed using the given mass of copper (64g) and the molar masses of copper and oxygen.

First, we need to find the moles of copper using the given mass and its molar mass:

moles of Cu = mass of Cu / molar mass of Cu

moles of Cu = 64g / 63.55 g/mol

moles of Cu ≈ 1.007 moles

Since the molar ratio of copper to copper oxide is 1:1, the moles of copper oxide formed will be the same as the moles of copper.

Now, we can find the mass of copper oxide:

mass of CuO = moles of Cu × molar mass of CuO

mass of CuO ≈ 1.007 moles × (63.55 g/mol + 16.00 g/mol)

mass of CuO ≈ 1.007 moles × 79.55 g/mol

mass of CuO ≈ 80.08g

So, the mass of copper oxide formed when 64g of copper reacts with oxygen is approximately 80.08 grams.