Question

Сколько молекул азота содержится в 280г молекулярного азота-N2

Answer 1

N=m/M
280/28=10(моль)
N=n*(6,02*10^23)(постоянная Авогадро)
10*(6,02*10^23)=6,02*10^24
Ответ: 6,02*10^24

Answer 2

Calculating the Number of Nitrogen Molecules in 280g of Molecular Nitrogen (N2)

To calculate the number of molecules of nitrogen in 280g of molecular nitrogen (N2), we can use the following steps:

1. Determine the Molar Mass of Nitrogen (N2) - The molar mass of nitrogen (N2) is 28.02 g/mol.

2. Calculate the Number of Moles of Nitrogen - We can use the formula: \[ \text{Number of moles} = \frac{\text{Mass (in grams)}}{\text{Molar mass}} \] - Substituting the values, we get: \[ \text{Number of moles} = \frac{280 \, \text{g}}{28.02 \, \text{g/mol}} = 9.989 \, \text{moles} \]

3. Convert Moles to Molecules - One mole of any substance contains Avogadro's number of molecules, which is approximately \(6.022 \times 10^{23}\) molecules/mol.

4. Calculate the Number of Molecules of Nitrogen - Multiplying the number of moles by Avogadro's number, we get: \[ \text{Number of molecules} = 9.989 \, \text{moles} \times 6.022 \times 10^{23} \, \text{molecules/mol} \approx 6.01 \times 10^{24} \, \text{molecules} \]

Therefore, there are approximately \(6.01 \times 10^{24}\) molecules of nitrogen in 280g of molecular nitrogen (N2).