Question

Напишите химические формулы веществ если известно что в состав их входят атом железа и 3 атома хлора 2 атома алюминия и три атома кислорода атом кальция атома углерода и 3 атома кислорода Вычислите относительные молекулярные массы данных веществ

Answer 1

А)FeCl3;   Mr= 56+ 3* 35,5=162,5
б)Al2O3  Mr= 2* 27+ 3*16=102
в) CaCO3      Mr= 40+12+ 3*16= 100

Answer 2

Chemical Formulas and Relative Molecular Mass Calculation

The given composition includes: - 1 atom of iron (Fe) - 3 atoms of chlorine (Cl) - 2 atoms of aluminum (Al) - 3 atoms of oxygen (O) - 1 atom of calcium (Ca) - 1 atom of carbon (C)

The chemical formulas for the substances can be determined as follows:

1. Iron Chloride: - Chemical Formula: FeCl3 - Explanation: Iron combines with 3 atoms of chlorine.

2. Aluminum Carbonate: - Chemical Formula: Al2(CO3)3 - Explanation: Aluminum combines with 3 carbonate groups, each containing 1 carbon and 3 oxygen atoms.

3. Calcium Carbonate: - Chemical Formula: CaCO3 - Explanation: Calcium combines with 1 carbonate group, containing 1 carbon and 3 oxygen atoms.

Relative Molecular Mass Calculation

Now, let's calculate the relative molecular masses of the given substances:

1. Iron Chloride (FeCl3): - Relative Atomic Mass of Fe: 55.85 g/mol - Relative Atomic Mass of Cl: 35.45 g/mol - Relative Molecular Mass of FeCl3: - (1 * 55.85) + (3 * 35.45) = 162.2 g/mol

2. Aluminum Carbonate (Al2(CO3)3): - Relative Atomic Mass of Al: 26.98 g/mol - Relative Atomic Mass of C: 12.01 g/mol - Relative Atomic Mass of O: 16.00 g/mol - Relative Molecular Mass of Al2(CO3)3: - (2 * 26.98) + (3 * (12.01 + 3 * 16.00)) = 233.99 g/mol

3. Calcium Carbonate (CaCO3): - Relative Atomic Mass of Ca: 40.08 g/mol - Relative Molecular Mass of CaCO3: - 40.08 + 12.01 + (3 * 16.00) = 100.09 g/mol

Therefore, the relative molecular masses of the given substances are: - Iron Chloride (FeCl3): 162.2 g/mol - Aluminum Carbonate (Al2(CO3)3): 233.99 g/mol - Calcium Carbonate (CaCO3): 100.09 g/mol