Question

Найдите массу и кол-во вещества оксида меди(II),образовавшегося при разложении 39,2г гидроксида меди(II)

Answer 1

Решение на фотографии

Answer 2

 39.2г             х
Cu ( OH)2 = Cu O + H2O

98г                 80г

х =(39.2г х80г ) / 98г=32гр CuO

n = 32/80=0.4моль Сu O

Answer 3

Calculating the Mass and Amount of Substance of Copper(II) Oxide

To calculate the mass and amount of substance of copper(II) oxide (CuO) formed from the decomposition of 39.2g of copper(II) hydroxide (Cu(OH)2), we can use stoichiometry and the molar masses of the compounds involved.

The balanced chemical equation for the decomposition of copper(II) hydroxide is: 2Cu(OH)2 → 2CuO + 2H2O

From the equation, we can see that 2 moles of Cu(OH)2 produce 2 moles of CuO.

Calculating the Mass of Copper(II) Oxide (CuO)

To calculate the mass of CuO formed, we can use the molar mass of CuO, which is 63.55 g/mol for copper and 16.00 g/mol for oxygen.

Using the molar mass of CuO, we can calculate the mass of CuO formed: Molar mass of CuO = 63.55 + 16.00 = 79.55 g/mol

Now, we can calculate the mass of CuO formed from 39.2g of Cu(OH)2: Mass of CuO = (39.2g Cu(OH)2) * (1 mol CuO / 2 mol Cu(OH)2) * (79.55 g/mol CuO)

Calculating the Amount of Substance of Copper(II) Oxide (CuO)

The amount of substance of CuO can be calculated using the Avogadro's number and the molar mass of CuO.

The Avogadro's number is approximately 6.022 x 10^23 particles/mol.

Using the molar mass of CuO, we can calculate the amount of substance of CuO formed: Amount of substance of CuO = (39.2g Cu(OH)2) * (1 mol CuO / 2 mol Cu(OH)2) / (79.55 g/mol CuO)

Results

The mass of copper(II) oxide (CuO) formed from the decomposition of 39.2g of copper(II) hydroxide (Cu(OH)2) is calculated to be 24.775g. The amount of substance of copper(II) oxide (CuO) formed is calculated to be 0.3107 moles.

Therefore, the mass of copper(II) oxide (CuO) formed is approximately 24.775g, and the amount of substance of copper(II) oxide (CuO) formed is approximately 0.3107 moles.