Question

H2+CuO = Cu+ H2OH2(0) -1e = H(+1)Надо где Н(+1) перед Н писать коэффицент 2 ?в скобках степени окисления

Answer 1

H₂° + Cu⁺²O⁻² ⇒Cu° + H₂⁺O⁻²
H₂° -2e ->2H⁺        1 в-ль, ок-ние
Cu⁺² + 2e ->Cu°     1 ок-ль, вос-ние

Answer 2

H2 + CuO = Cu + H2O

CuO is copper(II) oxide, which means that copper has an oxidation state of +2. When it reacts with H2, the copper is reduced to its elemental form with an oxidation state of 0, and the hydrogen is oxidized to form water.

The balanced equation is:

CuO + H2 = Cu + H2O

To balance the equation, you need to add a coefficient of 2 in front of H2O to ensure that the number of atoms of each element is the same on both sides of the equation:

CuO + H2 = Cu + 2H2O

So, you write the coefficient of 2 in front of H2O to balance the equation. The oxidation states of the elements involved in the reaction are also indicated in parentheses next to the chemical symbols.