Question

Осуществить превращения:Натрий-гидроксид;натрия-сульфат;натрия-сульфат бария.Записать уравнения в ионном виде и ОВР если возможноПОМОГИТЕ ПОЖАЛУЙСТА!!!1

Answer 1

1/2Na+2HOH=2NaOH+H2

Na(0)-e=Na(+)       2-окисление;восстановитель

2H(+)+2e=H2(0)     1-восстановление;окислитель

2/2NaOH+SO3=Na2SO4+H2O

      2OH(-)+SO3=SO4(2-)+H2O

3/Na2SO4+BaCl2=BaSO4+2NaCl

        Ba(2+)+SO4(2-)=BaSO4

Answer 2

Transformation of Sodium Hydroxide (NaOH)

The transformation of sodium hydroxide (NaOH) can be represented by the following equations:

In ionic form: NaOH → Na⁺ + OH⁻

In overall reaction form (OH⁻ as a hydroxide ion): NaOH → Na⁺ + OH⁻

In overall reaction form (OH⁻ as a hydroxide molecule): 2NaOH → Na₂O + H₂O

Transformation of Sodium Sulfate (Na₂SO₄)

The transformation of sodium sulfate (Na₂SO₄) can be represented by the following equations:

In ionic form: Na₂SO₄ → 2Na⁺ + SO₄²⁻

In overall reaction form: Na₂SO₄ → Na₂O + SO₃

Transformation of Barium Sulfate (BaSO₄)

The transformation of barium sulfate (BaSO₄) can be represented by the following equations:

In ionic form: BaSO₄ → Ba²⁺ + SO₄²⁻

In overall reaction form: BaSO₄ → BaO + SO₃

Please note that the above equations represent the transformation of the given compounds. If you are looking for specific reactions or conditions under which these transformations occur, please provide more details.