Question

1 Ba(OH)2+H3PO4= 2 MG(OH)2+HF= 3 KOH+SiO2= 4 Mn(OH)2= запишите 1 и 2 уравнение в ионном виде

Answer 1

1) 3Ba(OH)2 + 2H3PO4 → Ba3(PO4)2↓ + 6H2O
3Ba(2+) + 6OH(-) + 6H(+) + 2PO4(3-) → Ba3(PO4)2↓ + 6H2O

2) Mg(OH)2 + 2HF → MgF2 + 2H2O
Mg(OH)2 + 2H(+) + 2F(-) → Mg(2+) + 2F(-) + 2H2O
Mg(OH)2 + 2H(+) → Mg(2+) + 2H2O

3) 2KOH + SiO2 → K2SiO3 + H2O

4) Mn(OH)2 → MnO + H2O

Answer 2

Chemical Equations and Ionic Equations

1. Ba(OH)2 + H3PO4 = 2 Mg(OH)2 + HF 2. KOH + SiO2 = 4 Mn(OH)2

To write the equations in ionic form, we need to break down the compounds into their respective ions.

1. Ba(OH)2 + H3PO4 = 2 Mg(OH)2 + HF

The balanced chemical equation for this reaction is:

Ba(OH)2 + 2 H3PO4 = Ba3(PO4)2 + 6 H2O

To write the equation in ionic form, we need to separate the compounds into their respective ions:

Ba(OH)2 (aq) + 2 H3PO4 (aq) = Ba3(PO4)2 (aq) + 6 H2O (l)

Breaking down the compounds into ions:

Ba2+ (aq) + 2 OH- (aq) + 2 H+ (aq) + 2 H2PO4- (aq) = Ba3(PO4)2 (aq) + 6 H2O (l)

2. KOH + SiO2 = 4 Mn(OH)2

The balanced chemical equation for this reaction is:

2 KOH + SiO2 = K2SiO3 + H2O

To write the equation in ionic form, we need to separate the compounds into their respective ions:

2 KOH (aq) + SiO2 (s) = K2SiO3 (aq) + H2O (l)

Breaking down the compounds into ions:

2 K+ (aq) + 2 OH- (aq) + SiO2 (s) = K2SiO3 (aq) + H2O (l)

Please note that the ionic equations provided here are simplified representations of the reactions. In reality, there may be additional ions or species present in the solution.