
Определить эквивалентную массу металла, если хлор, выделившийся при действии концентрированной HCl
на 5,21 г MnO2 , образует с этим металлом 5,70 г хлоридаПомогите пожалуйста, очень надо))))))

Ответы на вопрос

2) m Me = 5.7-4.252 = 1.448 г;
3) М экв. Cl в хлоридах = 35.5*(1/1) = 35.5 г/моль; по з. эквив-в, М экв. Ме = 1.448*(35.5/4.252) = 12 г/моль.



Calculation of Equivalent Mass of Metal
To determine the equivalent mass of the metal, we need to consider the reaction between the metal and the chlorine gas. The balanced chemical equation for the reaction can be written as:
Metal + Chlorine gas → Metal chloride
From the given information, we know that 5.21 g of MnO2 reacts with chlorine gas to form 5.70 g of metal chloride.
To find the equivalent mass of the metal, we need to calculate the number of moles of MnO2 and metal chloride formed in the reaction.
1. Calculate the number of moles of MnO2: - The molar mass of MnO2 (manganese dioxide) is 86.94 g/mol (54.94 g/mol for Mn + 32.00 g/mol for O). - Using the formula: moles = mass / molar mass, we can calculate the number of moles of MnO2: - Moles of MnO2 = 5.21 g / 86.94 g/mol = 0.0598 mol
2. Calculate the number of moles of metal chloride: - The molar mass of metal chloride is unknown, so we'll use the given mass of 5.70 g to calculate the number of moles. - Moles of metal chloride = 5.70 g / molar mass of metal chloride
3. Determine the equivalent mass of the metal: - The equivalent mass of a substance is the mass of the substance that reacts with or replaces one mole of hydrogen ions (H+). - Since the metal chloride is formed by the reaction of the metal with chlorine gas, the equivalent mass of the metal is equal to the molar mass of the metal chloride. - Equivalent mass of the metal = molar mass of metal chloride
To find the molar mass of the metal chloride, we need to know the identity of the metal. Unfortunately, the given information does not provide the identity of the metal. Therefore, we cannot determine the exact equivalent mass of the metal without additional information.
Please provide the identity of the metal so that we can calculate the equivalent mass accurately.


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